可重复使用的代码,可在双击时使矩形不透明度为零

Question

我有一些矩形,当你双击它们所在的屏幕时,我想让它"出现":

<StackPanel>
    <Rectangle Name="MyRect1" Opacity="0" Height="100" DoubleTapped="MyRect1_DoubleTapped" Fill="Aqua" />
    <Rectangle Name="MyRect2" Opacity="0" Height="100" DoubleTapped="MyRect2_DoubleTapped" Fill="Black"/>
    <Rectangle Name="MyRect3" Opacity="0" Height="100" DoubleTapped="MyRect3_DoubleTapped" Fill="Blue"/>
</StackPanel>

我目前的代码背后 - 这有效:

private void MyRect1_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect1.Opacity = 1;
}

private void MyRect2_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect2.Opacity = 1;
}

private void MyRect3_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    MyRect3.Opacity = 1;
}

由于我可能需要十几个或更多这些出现的矩形,有没有办法只为所有这些使用一个事件处理程序？

即,而不是为每个矩形都有一个处理程序,有类似的东西:

<StackPanel>
    <Rectangle Name="MyRect1" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Aqua" />
    <Rectangle Name="MyRect2" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Black"/>
    <Rectangle Name="MyRect3" Opacity="0" Height="100" DoubleTapped="MyRect_DoubleTapped" Fill="Blue"/>
</StackPanel>

使用单个处理程序MyRect_DoubleTapped:

private void MyRect_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    (some way to tell which rectangle was DoubleTapped)
    (the identified rectangle).Opacity = 1;
}

Answer 1

您可以使用它sender来知道哪一个被轻敲

private void MyRect_DoubleTapped(object sender, DoubleTappedRoutedEventArgs e)
{
    Rectangle myRect = (Rectangle)sender;
    myRect.Opacity = 1;
}

这sender是引发事件的对象.