Jon*_*Doe -4 java compiler-errors exception try-catch
我正在编写一个 Java 文件,但是当我尝试编译它时,我不断收到 3 条错误消息:
reader.java:35: 错误:'try' 没有 'catch'、'finally' 或资源声明 try
reader.java:48: 错误:'catch' 没有 'try' catch(IOException e)
reader.java:52: 错误: 'catch' 没有 'try' catch(Exception e)
3 错误
为什么?我错过了什么?这是我的代码:
public static void processRecords(String filenameIn, Person[] personArray)
{
try
{
FileReader fr = new FileReader(filenameIn);
BufferedReader reader = new BufferedReader(fr);
reader.readLine();
for (int i = 0; i <personArray.length; i++)
{
String[] data = reader.readLine().split("/t");
personArray[i] = new Person(Integer.parseInt(data[0]), data[1], data[2], Integer.parseInt(data[3]));
}
}
reader.close();
catch(IOException e)
{
System.out.println("ERROR: WRONG FILE " + e.toString());
}
catch(Exception e)
{
System.out.println("ERROR" + e.toString());
}
}
Run Code Online (Sandbox Code Playgroud)
不能放在和reader.close()
之间。要么把它放在一个块中,要么使用. 喜欢,try
catch
finally
try-with-resources
try (BufferedReader reader = new BufferedReader(new FileReader(filenameIn))) {
reader.readLine();
for (int i = 0; i < personArray.length; i++) {
String[] data = reader.readLine().split("/t"); // <-- should be \\t for tab.
personArray[i] = new Person(Integer.parseInt(data[0]), data[1],
data[2], Integer.parseInt(data[3]));
}
} catch (IOException e) {
System.out.println("ERROR: WRONG FILE " + e.toString());
} catch (Exception e) {
System.out.println("ERROR" + e.toString());
}
Run Code Online (Sandbox Code Playgroud)
或与finally
块,
BufferedReader reader = null;
try {
reader = new BufferedReader(new FileReader(filenameIn));
reader.readLine();
for (int i = 0; i < personArray.length; i++) {
String[] data = reader.readLine().split("\\t"); // <-- to split on tab.
personArray[i] = new Person(Integer.parseInt(data[0]),
data[1], data[2], Integer.parseInt(data[3]));
}
} catch (IOException e) {
System.out.println("ERROR: WRONG FILE " + e.toString());
} catch (Exception e) {
System.out.println("ERROR" + e.toString());
} finally {
if (reader != null) {
reader.close();
}
}
Run Code Online (Sandbox Code Playgroud)