如何从Rust中的C联合访问值?

Phi*_*wig 2 unions rust

我正试图SDL_PollEvent从C库中调用该函数SDL2.我知道已有包装,但我想创建自己的包装,只是为了学习.该函数需要一个指向此C联合的指针:

typedef union{
  Uint8 type;
  SDL_ActiveEvent active;
  SDL_KeyboardEvent key;
  SDL_MouseMotionEvent motion;
  SDL_MouseButtonEvent button;
  SDL_JoyAxisEvent jaxis;
  SDL_JoyBallEvent jball;
  SDL_JoyHatEvent jhat;
  SDL_JoyButtonEvent jbutton;
  SDL_ResizeEvent resize;
  SDL_ExposeEvent expose;
  SDL_QuitEvent quit;
  SDL_UserEvent user;
  SDL_SysWMEvent syswm;
} SDL_Event;
Run Code Online (Sandbox Code Playgroud)

我已经导入了这样的函数:

#[link(name = "SDL2")]
extern "C" {
    fn SDL_PollEvent(event: *mut SdlEvent) -> libc::c_int;
} 
Run Code Online (Sandbox Code Playgroud)

并声明了这样的类型:

type SdlEvent = [u8; 56];                                                    
Run Code Online (Sandbox Code Playgroud)

现在我可以调用SDL_Pollevent并检索typeunion 的值:

// According to sizeof(SDL_Event), the unit is 56 bytes
let mut sdl_event: SdlEvent = [0; 56];

unsafe { SDL_PollEvent(&mut sdl_event) };

let event_type: u32 = u32::from_be((sdl_event[0] as u32) << 24 | (sdl_event[1] as u32) << 16 |
                                   (sdl_event[2] as u32) << 8 |
                                   (sdl_event[3] as u32));

match event_type {                              
    0x100 => {
        Event {                     
             // 0x100 is SDL_QUIT -> quit application
     }
    }                                      
    0x200 => {
        Event { // SDL_KEYDOWN
             // How can I 
     }
    }                                      
}
Run Code Online (Sandbox Code Playgroud)

这工作正常,但现在我想知道哪个键被按下,这意味着我需要检索key该类型的值SDL_KeyboardEvent.我怎样才能做到这一点?

She*_*ter 5

工会基本上与C类似,这意味着它们不安全.从Rust 1.16开始,它们也是一个不稳定的特性:

#![feature(untagged_unions)]

extern crate libc;

// Definitions for SDL_ActiveEvent, SDL_KeyboardEvent, etc.

#[repr(C)]
union SDLEvent {
    typ: libc::uint8_t,
    active: SDL_ActiveEvent,
    key: SDL_KeyboardEvent,
    // All the rest
}

fn thing(event: SDLEvent) {
    unsafe { 
        println!("{}", event.typ);
    }
}
Run Code Online (Sandbox Code Playgroud)