创建基本存储库类时出错

Question

import org.springframework.data.jpa.repository.support.JpaEntityInformation;
import org.springframework.data.jpa.repository.support.QueryDslJpaRepository;
import org.springframework.data.querydsl.EntityPathResolver;
import org.springframework.data.repository.NoRepositoryBean;
import org.springframework.transaction.annotation.Transactional;

import javax.persistence.EntityManager;

@NoRepositoryBean
public class RepositorySupportImpl<T> extends QueryDslJpaRepository<T, Integer> implements RepositorySupport<T> {

    private EntityManager entityManager;


    public RepositorySupportImpl(JpaEntityInformation<T, Integer> entityInformation, EntityManager entityManager, EntityManager entityManager1) {
    super(entityInformation, entityManager);
    this.entityManager = entityManager1;
    }

    public RepositorySupportImpl(JpaEntityInformation<T, Integer> entityInformation, EntityManager entityManager, EntityPathResolver resolver, EntityManager entityManager1) {
    super(entityInformation, entityManager, resolver);
    this.entityManager = entityManager1;
    }

    @Override
    public EntityManager getEntityManager() {
    return this.entityManager;
    }

@Transactional
@Override
public <S extends T> S save(final S entity) {
    this.getEntityManager().persist(entity);
    return entity;
}

}

import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.querydsl.QueryDslPredicateExecutor;

import javax.persistence.EntityManager;

public interface RepositorySupport<T> extends JpaRepository<T, Integer>, QueryDslPredicateExecutor<T> {

    EntityManager getEntityManager();

}

在我的配置类中，我有 repositoryBaseClass = RepositorySupportImpl.class

但我收到此错误：

org.springframework.beans.factory.UnsatisfiedDependencyException：创建名为“registerService”的bean时出错：通过字段“userRepository”表达的不满意依赖；嵌套异常是 org.springframework.beans.factory.BeanCreationException：创建名为“userRepository”的 bean 时出错：调用 init 方法失败；嵌套异常是 java.lang.IllegalStateException：在类 ca.lighthouse.repository.RepositorySupportImpl 上找不到合适的构造函数来匹配给定的参数：[class org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation, class com.sun.proxy .$Proxy52]。确保你实现了一个带有这些的构造函数

Answer 1

我刚才遇到了同样的问题，经过一些调试后，我找到了解决方案：

确保您只有一个EnableJpaRepositories注释并且它指向实现类（而不是接口）：

@EnableJpaRepositories(repositoryBaseClass = GenericJpaRepositoryImpl.class)

我希望它可以帮助将来的某个人;)