如何在Bazel中静态链接系统库？

Question

如何在大多数静态模式(linkstatic = 1)中静态链接系统库？我试图使用"-Wl,-Bstatic -lboost_thread -Wl,-Bdynamic"或"-Wl,-Bstatic"," - lboost_thread"," - WI,-Bdynamic",但它们都没有奏效.我不想在系统中硬编码libboost_thread.a的路径.

cc_binary(
    name = "main",
    srcs = [
        "main.cpp",
    ],
    linkopts = [
        "-lboost_thread",
    ],
)

boost_thread库作为动态库链接.

ldd bazel-bin/main
linux-vdso.so.1
libboost_thread.so.1.54.0 => /usr/lib/x86_64-linux-gnu/libboost_thread.so.1.54.0
libstdc++.so.6 => /usr/lib/x86_64-linux-gnu/libstdc++.so.6
...

Answer 1

在您的WORKSPACE文件中定义一个外部存储库...

new_local_repository(
    name = "boost_thread",
    path = "/usr/lib/x86_64-linux-gnu",
    build_file = "boost_thread.BUILD"
)

创建一个boost_thread.BUILD文件

cc_library(
   name = "lib",
   srcs = ["libboost_thread.a"],
   visibility = ["//visibility:public"],
)

然后在您的cc_binary规则中添加

deps = ["@boost_thread//:lib",],

然后扔一个

linkstatic = 1

为了安全起见。