The*_*r23 3 python dataframe pandas
假设我有两个形式的熊猫:
>>> df
A B C
first 62.184209 39.414005 60.716563
second 51.508214 94.354199 16.938342
third 36.081861 39.440953 38.088336
>>> df1
A B C
first 0.828069 0.762570 0.717368
second 0.136098 0.991668 0.547499
third 0.120465 0.546807 0.346949
>>>
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我生成的:
import pandas as pd
import numpy as np
df = pd.DataFrame(np.random.random([3, 3])*100,
columns=['A', 'B', 'C'], index=['first', 'second', 'third'])
df1 = pd.DataFrame(np.random.random([3, 3]),
columns=['A', 'B', 'C'], index=['first', 'second', 'third'])
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你能找到最聪明,最快捷的方法来获得:
A B C
first 62.184209 39.414005 60.716563
first_s 0.828069 0.762570 0.717368
second 51.508214 94.354199 16.938342
second_s 0.136098 0.991668 0.547499
third 36.081861 39.440953 38.088336
third_s 0.120465 0.546807 0.346949
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?
我想我可以做一个for循环说从第二行的第一行和奇数行中取偶数行,但它对我来说似乎不是很有效.
试试这个:
In [501]: pd.concat([df, df1.set_index(df1.index + '_s')]).sort_index()
Out[501]:
A B C
first 62.184209 39.414005 60.716563
first_s 0.828069 0.762570 0.717368
second 51.508214 94.354199 16.938342
second_s 0.136098 0.991668 0.547499
third 36.081861 39.440953 38.088336
third_s 0.120465 0.546807 0.346949
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