Kir*_*kov 8 java serialization json timestamp jackson
我有这样的字符串:
{
"debug":"false",
"switchTime":"2017-04-12 17:04:42.896026"
}
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我试图通过这种方法获得对象:
new ObjectMapper().readValue(string, MyObject.class);
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和MyObject类:
class MyObject {
private Boolean debug;
private Timestamp switchTime;
//...getters, setters, constructors
}
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我有这样的例外:
com.fasterxml.jackson.databind.exc.InvalidFormatException:
Can not deserialize value of type java.sql.Timestamp from String
"2017-04-12 17:04:42.896026": not a valid representation (error:
Failed to parse Date value '2017-04-12 17:04:42.896026':
Can not parse date "2017-04-12 17:04:42.896026Z": while it seems
to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSS'Z'',
parsing fails (leniency? null)) at [Source:
{"debug":"false", "switchTime":"2017-04-12 17:04:42.896026"};
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我不明白为什么......如果我在调试模式下使用Timestamp.valueOf()和"2017-04-12 17:04:42.896026" - 我有成功
Jus*_*ose 26
我认为你需要使用@JsonFormat注释设置预期的日期/时间格式,如下所示.
class MyObject {
private Boolean debug;
@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS")
private Timestamp switchTime;
//...getters, setters, constructors
}
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您还可以将时区设置为 @JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS",timezone="PST")
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