我注意到,根据列表的创建方式,底层的int数组会发生变化:
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
import java.util.Random;
public class Shuffling {
static Integer[] intArr = {1, 2, 3, 4, 5};
static Random random = new Random(7);
public static void main(String[] args) {
List<Integer> intList = new ArrayList<Integer>(Arrays.asList(intArr));
Collections.shuffle(intList, random);
System.out.println("List after shuffling: " + intList);
System.out.println("intArr: " + Arrays.toString(intArr));
//OUTPUT:
//List after shuffling: [5, 4, 1, 3, 2]
//intArr: [1, 2, 3, 4, 5]
List<Integer> intList2 = Arrays.asList(intArr);
Collections.shuffle(intList2, random);
System.out.println("List2 after shuffling: " + intList2);
System.out.println("intArr: " + Arrays.toString(intArr));
//OUTPUT:
//List2 after shuffling: [5, 3, 4, 2, 1]
//intArr: [5, 3, 4, 2, 1]
}
}
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为什么会这样?
Arrays.asList() 构造一个由原始数组支持的特殊列表.
这就是为什么列表不支持Collection接口的(可选)add()和remove()方法(使用数组不可能).
有趣的是,返回的类被调用ArrayList,尽管不要混淆java.util.ArrayList.
System.out.println(
Arrays.asList("1", "2", "3")
.getClass().getName()
);
// Output: java.util.Arrays$ArrayList
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