错误:在C Prog中,Assignment在没有强制转换的情况下从Integer生成指针

Question

每当我运行程序"Assignment在没有强制转换的情况下从Integer发出指针"时,我都会收到此错误.我的代码写在下面....请帮助......谢谢

struct student {
       char studentID[6];
       char name[31];
       char course [6];
};
struct student *array[MAX];
struct student dummy;
int recordCtr=0;

int read(){
     FILE *stream = NULL;
     int ctr;
     char linebuffer[45];
     char delims[]=", ";
     char *number[3];
     char *token = NULL;

     stream = fopen("student.txt", "rt");

     if (stream == NULL) stream = fopen("student.txt", "wt");
     else {
          printf("\nReading the student list directory. Wait a moment please...");
          while(!feof(stream)){
                array[recordCtr]=(struct student*)malloc(sizeof(struct student)); 
                while(!feof(stream)) {
                     fgets(linebuffer, 46, stream);
                     token = strtok(linebuffer, delims); //This is where the error appears
                     ctr=0;
                     while(token != NULL){
                          strcpy(number[ctr], linebuffer);
                          token = strtok(NULL, delims);  //This is where the error appears
                          ctr++;
                     }
                     strcpy(array[recordCtr] -> studentID,number[0]);
                     strcpy(array[recordCtr] -> name,number[1]);  
                     strcpy(array[recordCtr] -> course,number[2]);                    

                }                     
          recordCtr++;
          }
     recordCtr--;
     fclose(stream);
     }

Answer 1

您没有(至少在粘贴的代码中)#included定义strtok函数的标头.在C中,假定还没有原型的函数返回int.因此,我们在没有强制转换的情况下从int(函数结果)分配到char*(类型token).

当然,我们不想要演员.我们想要#include标题,以便编译器理解strtok返回的内容.

但是,strtok如果还有其他任何可以完成工作的话,我们也不会真的想要使用它们.它有许多不明显的限制.对于健壮的字符串解析,请尝试sscanf.