swift 3.1如何从CSV获取数组或字典
big*_*ree 23 csv parsing swift3
我怎样才能在这种CSV文件中使用数据？或者我如何打印"内部"列的第2行值并将其分配给属性/实体？
我有这样的文件,我从excel文件转换为Numbers,我想获取每列的数据并使用它们.
以数字打开的原始CSV文件:
我得到的控制台输出:
使用这种方法:
func readDataFromCSV(fileName:String, fileType: String)-> String!{
guard let filepath = Bundle.main.path(forResource: fileName, ofType: fileType)
else {
return nil
}
do {
var contents = try String(contentsOfFile: filepath, encoding: .utf8)
contents = cleanRows(file: contents)
return contents
} catch {
print("File Read Error for file \(filepath)")
return nil
}
}
func cleanRows(file:String)->String{
var cleanFile = file
cleanFile = cleanFile.replacingOccurrences(of: "\r", with: "\n")
cleanFile = cleanFile.replacingOccurrences(of: "\n\n", with: "\n")
// cleanFile = cleanFile.replacingOccurrences(of: ";;", with: "")
// cleanFile = cleanFile.replacingOccurrences(of: ";\n", with: "")
return cleanFile
}
解决方案感谢Jens Meder
运用
func csv(data: String) -> [[String]] {
var result: [[String]] = []
let rows = data.components(separatedBy: "\n")
for row in rows {
let columns = row.components(separatedBy: ";")
result.append(columns)
}
return result
}
在viewDidLoad中
var data = readDataFromCSV(fileName: kCSVFileName, fileType: kCSVFileExtension)
data = cleanRows(file: data!)
let csvRows = csv(data: data!)
print(csvRows[1][1]) // UXM n. 166/167
Jen*_*der 21
你想要做的是将字符串分成行然后分成列(基本上是字符串的二维数组).Swift已经为结构提供了components方法String.
func csv(data: String) -> [[String]] {
var result: [[String]] = []
let rows = data.components(separatedBy: "\n")
for row in rows {
let columns = row.components(separatedBy: ";")
result.append(columns)
}
return result
}
然后您可以通过以下方式访问任何值
var data = readDataFromCSV(fileName: kCSVFileName, fileType: kCSVFileExtension)
data = cleanRows(file: data)
let csvRows = csv(data: data)
print(csvRows[1][1]) //UXM n. 166/167.
- 如果值中有特殊字符，例如字符串之一中的“;”，这将不起作用。还有更多的转义规则。最好找一个成熟的库来为你解析。 (5认同)
wli*_*xcc 19
从iOS15开始官方有一个新的框架叫TabularData，尝试使用它。
import TabularData
let url = Bundle.main.url(forResource: "csvFileName", withExtension: "csv")!
let result = try? DataFrame(contentsOfCSVFile: url)
print(result)
然后你可以将它们转换成你需要的数据模型
- 这应该是 2022 年公认的答案 (4认同)
小智 12
?这是用于 Swift 4.2 的 CSV 文件，地址为 20181208
var dataArray : [String] = []
if let path = Bundle.main.path(yourfile: "svenskaidiom", ofType: "csv")
{
dataArray = []
let url = URL(fileURLWithPath: path)
do {
let data = try Data(contentsOf: url)
let dataEncoded = String(data: data, encoding: .utf8)
if let dataArr = dataEncoded?.components(separatedBy: "\r\n").map({ $0.components(separatedBy: ";") })
{
for line in dataArr
{
dataArray?.append(line)
}
}
}
catch let jsonErr {
print("\n Error read CSV file: \n ", jsonErr)
}
}
Rob*_*b.R 10
Swift 5.0 .scanLocaion 和 .scanUpTo() 在 iOS13 中已弃用。这是 Chhaileng 答案的工作版本。
func openCSV(fileName:String, fileType: String)-> String!{
guard let filepath = Bundle.main.path(forResource: fileName, ofType: fileType)
else {
return nil
}
do {
let contents = try String(contentsOfFile: filepath, encoding: .utf8)
return contents
} catch {
print("File Read Error for file \(filepath)")
return nil
}
}
func parseCSV(){
let dataString: String! = openCSV(fileName: "MeislinDemo", fileType: "csv")
var items: [(String, String, String)] = []
let lines: [String] = dataString.components(separatedBy: NSCharacterSet.newlines) as [String]
for line in lines {
var values: [String] = []
if line != "" {
if line.range(of: "\"") != nil {
var textToScan:String = line
var value:String?
var textScanner:Scanner = Scanner(string: textToScan)
while !textScanner.isAtEnd {
if (textScanner.string as NSString).substring(to: 1) == "\"" {
textScanner.currentIndex = textScanner.string.index(after: textScanner.currentIndex)
value = textScanner.scanUpToString("\"")
textScanner.currentIndex = textScanner.string.index(after: textScanner.currentIndex)
} else {
value = textScanner.scanUpToString(",")
}
values.append(value! as String)
if !textScanner.isAtEnd{
let indexPlusOne = textScanner.string.index(after: textScanner.currentIndex)
textToScan = String(textScanner.string[indexPlusOne...])
} else {
textToScan = ""
}
textScanner = Scanner(string: textToScan)
}
// For a line without double quotes, we can simply separate the string
// by using the delimiter (e.g. comma)
} else {
values = line.components(separatedBy: ",")
}
// Put the values into the tuple and add it to the items array
let item = (values[0], values[1], values[2])
items.append(item)
print(item.0)
print(item.1)
print(item.2)
}
}
}
- 该解析器（与本页上的任何解析器一样）存在缺陷。它从按换行符分割行开始，这是一个错误的假设。csv 文件可能包含换行符，因为它的值用双引号引起来。因此，唯一的方法是从一开始就正确解析，使用迷你状态机，并且不要假设任何事情 (6认同)
斯威夫特4
有时CSV文件更加复杂，例如特殊字符（例如逗号），其值用双引号引起来，如下所示：
Hello, "Complicated String, with a comma inside", 123
在这种情况下，我使用：
let dataString: String! = String.init(data: data!, encoding: .utf8)
var items: [(String, String, String)] = []
let lines: [String] = dataString.components(separatedBy: NSCharacterSet.newlines) as [String]
for line in lines {
var values: [String] = []
if line != "" {
if line.range(of: "\"") != nil {
var textToScan:String = line
var value:NSString?
var textScanner:Scanner = Scanner(string: textToScan)
while textScanner.string != "" {
if (textScanner.string as NSString).substring(to: 1) == "\"" {
textScanner.scanLocation += 1
textScanner.scanUpTo("\"", into: &value)
textScanner.scanLocation += 1
} else {
textScanner.scanUpTo(",", into: &value)
}
values.append(value! as String)
if textScanner.scanLocation < textScanner.string.count {
textToScan = (textScanner.string as NSString).substring(from: textScanner.scanLocation + 1)
} else {
textToScan = ""
}
textScanner = Scanner(string: textToScan)
}
// For a line without double quotes, we can simply separate the string
// by using the delimiter (e.g. comma)
} else {
values = line.components(separatedBy: ",")
}
// Put the values into the tuple and add it to the items array
let item = (values[0], values[1], values[2])
items.append(item)
print(item.1)
print(item.2)
print(item.3)
}
}
它只是用Swift 4编写的，原文来自https://www.appcoda.com/core-data-preload-sqlite-database/