Matplotlib 散布 3d 颜色

Question

我的问题是，我想以与所有其他点不同的颜色绘制此结构的 0,0,0 点。但是该图仅以所选颜色呈现轮廓，而该球的内部仍与其他点颜色相同。我不明白这是如何工作的。

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np



fig = plt.figure()
ax = fig.gca(projection='3d')
ax.set_aspect("equal")

for x in range(-count,count+1):
    for y in range(-count,count+1):
        for z in range(-count,count+1):
            if x == 0 and y == 0 and z == 0:
                ax.scatter(x,y,z, color="g",s=100) #here is the problem
            elif ((x+y+z+3*count)%2) == 0:
                ax.scatter(*zip([x,y,z]), color="r")
            else:
                ax.scatter(*zip([x,y,z]), color="b")

     plt.show()

Answer 1

您可以使用参数 edgecolor和facecolor来设置边和面的颜色。

ax.scatter(x,y,z, s=100, edgecolor="r", facecolor="gold")

或者，您可以使用参数c直接设置颜色，

ax.scatter(x,y,z, s=100, c="limegreen")

或设置应通过颜色图用颜色表示的值范围。最后一种方法还允许将所有点放在单个散点图中，如下所示：

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.gca(projection='3d')
ax.set_aspect("equal")

count = 2
x = range(-count,count+1)
X,Y,Z = np.meshgrid(x,x,x)

c = np.zeros_like(X, dtype=np.float)
c[((X+Y+Z+3*count)%2) == 0] = 0.5
c[count,count,count] = 1

s = np.ones_like(X)*25
s[count,count,count] = 100
ax.scatter(X,Y,Z, c=c,s=s, cmap="brg")

plt.show()