Mar*_*tin 24 observable typescript ionic2 angular
我试图通过使用来避免嵌套的observable forkjoin.当前(嵌套)版本如下所示:
this.http.get('https://testdb1.firebaseio.com/.json').map(res => res.json()).subscribe(data_changes => {
this.http.get('https://testdb2.firebaseio.com/.json').map(res => res.json()).subscribe(data_all => {
/* Do this once resolved */
this.platform.ready().then(() => {
this.storage.set('data_changes', data_changes);
this.storage.set('data_all', data_all);
document.getElementById("chart").innerHTML = "";
this.createChart();
});
});
},
err => {
this.platform.ready().then(() => {
console.log("server error 2");
document.getElementById("chart").innerHTML = "";
this.createChart();
});
});
}
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我可以将第一部分重写为:
Observable.forkJoin(
this.http.get('https://testdb1.firebaseio.com/.json').map((res: Response) => res.json()),
this.http.get('https://testdb2.firebaseio.com/.json').map((res: Response) => res.json())
)
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但我不知道如何添加.subscribe方法来访问data_changes和data_all.
看另一个例子,我知道它应该看起来像.subscribe(res => this.combined = {friends:res[0].friends, customer:res[1]});,但我不知道如何适应我的例子.
Viv*_*shi 38
尝试使用combineLatest而不是forkJoin:
用combineLatest:
const combined = Observable.combineLatest(
this.http.get('https://testdb1.firebaseio.com/.json').map((res: Response) => res.json()),
this.http.get('https://testdb2.firebaseio.com/.json').map((res: Response) => res.json())
)
combined.subscribe(latestValues => {
const [ data_changes , data_all ] = latestValues;
console.log( "data_changes" , data_changes);
console.log( "data_all" , data_all);
});
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您也可以通过forkJoin处理它,但forkJoin将在所有调用完成并返回结果时返回数据,但在combineLatest中当任何observable发出值时,从每个调用发出最新值.
用forkJoin:
const combined = Observable.forkJoin(
this.http.get('https://testdb1.firebaseio.com/.json').map((res: Response) => res.json()),
this.http.get('https://testdb2.firebaseio.com/.json').map((res: Response) => res.json())
)
combined.subscribe(latestValues => {
const [ data_changes , data_all ] = latestValues;
console.log( "data_changes" , data_changes);
console.log( "data_all" , data_all);
});
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调用两个并检查控制台日志,你会明白的.
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