使用#selector传递参数

Question

我是Swift的初学者，正在尝试通过NotificationCenter初始化功能。“ ViewController.swift”中的观察者调用function reload：

override func viewDidLoad() {
    super.viewDidLoad()
    NotificationCenter.default.addObserver(self, selector: #selector(reload), name: NSNotification.Name(rawValue: "reload"), object: nil)
}

func reload(target: Item) {
    print(target.name)
    print(target.iconName)
}

...的参数为class Ítem：

class Item: NSObject {
    let name: String
    let iconName: String
    init(name: String, iconName: String) {
        self.name = name
        self.iconName = iconName
    }
}

该通知从“ menu.swift”发布：

class menu: UIView, UITableViewDelegate, UITableViewDataSource {

let items: [Item] = {
    return [Item(name: "Johnny", iconName: "A"), Item(name: "Alexis", iconName: "B"), Item(name: "Steven", iconName: "C")]
}()

...

func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
    NotificationCenter.default.post(name: NSNotification.Name(rawValue: "reload"), object: items[indexPath.row])
    }

如何将items[indexPath.row]“ menu.swift”中的对象值分配给reload“ ViewController.swift”中的函数参数？

Answer 1

如果要在注册到的类周围传递对象NotificationCenter，则应将其放入.userInfo传递给观察者函数的通知对象字典中：

NotificationCenter.default.addObserver(self, selector: #selector(reload), name: Notification(name: "reload"), object: nil)

-

let userInfo = ["item": items[indexPath.row]]
NotificationCenter.default.post(name: "reload", object: nil, userInfo: userInfo)

-

func reload(_ notification: Notification) {
  if let target = notification.userInfo?["item"] as? Item {
    print(target.name)
    print(target.iconName)
  }
}