在Kotlin中嵌套的lambda调用

ars*_*v31 17 kotlin

在Kotlin中嵌套lambda调用时,我如何明确地引用child和parent的it元素?例如:

data class Course(var weekday: Int, var time: Int, var duration: Int)
var list1 = mutableListOf<Course>()
var list2 = mutableListOf<Course>()
// populate list1 and list2
// exclude any element from list1 if it has the same time and weekday as any element from list2
list1.filter { list2.none{it.weekday == it.weekday && it.time == it.time} }
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zsm*_*b13 28

it总是引用最里面的lambda参数,要访问外部参数,你必须命名它们.例如:

list1.filter { a -> list2.none { b -> a.weekday == b.weekday && a.time == b.time} }
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(你可以把内部的那个留下来it,但是如果你这么说的话,它会更好一点,在我看来.)

编辑: @ mfulton26链接下面的相关文档,有关详细信息,请参阅.

  • 您可以添加相关文档的链接.即[高阶函数](http://kotlinlang.org/docs/reference/lambdas.html#higher-order-functions)和[`it`:单个参数的隐式名称](http:// kotlinlang.组织/文档/参考/ lambdas.html#它隐名对的一单参数). (3认同)
  • 您还可以使用[Lambdas中的解构(自1.1起)](http://kotlinlang.org/docs/reference/multi-declarations.html#destructuring-in-lambdas-since-11).例如:`list1.filter {(weekday1,time1) - > list2.none {(weekday2,time2) - > weekday1 == weekday2 && time1 == time2}}`. (2认同)