Cra*_*aig 2 jquery jquery-templates
我正在尝试使用具有组头的jQuery模板插件来创建模板.由于它是数据驱动的,因此之前不知道组头.我的模板是:
<div class='category'>${Category}</div>
<div class='service'><a service_id='${Id}'>${Name}</a></div>
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我的数据是:
var movies = [
{ Name: "Meet Joe Black", Category: "First", Id: 1 },
{ Name: "The Mighty", Category: "First", Id: 2 },
{ Name: "City Hunter", Category: "First", Id: 3 },
{ Name: "A movie", Category: "Second", Id: 4 },
{ Name: "Blade Runner", Category: "Third", Id: 5 }
];
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我想要输出
<div class='category'>First</div>
<div class='service'><a service_id='1'>Meet Joe Black</a></div>
<div class='service'><a service_id='2'>The Mighty</a></div>
<div class='service'><a service_id='3' >City Hunter</a></div>
<div class='category'>Second</div>
<div class='service'><a service_id='4'>A movie</a></div>
<div class='category'>Third</div>
<div class='service'><a service_id='5'>Blade Runner</a></div>
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我注意到如何正确设置模板以实现此目的.
您需要转动数据,如下所示:
var categories = {};
$.each(movies, function(i, m) {
if(!categories[m.Category]) categories[m.Category] = [m];
else categories[m.Category].push(m);
});
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然后设置模板以循环,例如:
<script id="mTemplate" type="text/x-jquery-tmpl">
{{each(category, movies) $data}}
<div class='category'>${category}</div>
{{each(index, movie) movies}}
<div class='service'><a service_id='${movie.Id}'>${movie.Name}</a></div>
{{/each}}
{{/each}}
</script>
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然后你只需调用你的模板传递该透视数据对象作为唯一的参数,如下所示:
$("#mTemplate").tmpl(categories).appendTo("#output");
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当然,更好的选择是在服务器端进行转换(并且可能使用整体数组的不同格式......这将简化模板),不确定这是否是一个选项.