gyu*_*don 11 io performance file rust
为了比较C和Rust之间的文件I/O性能,我将"test"写入100,000,000次文件并从文件中读取4个字节100,000,000次.
与C相比,Rust代码花费了超过450倍的sys时间用于写入,140次用于读取.
我怀疑有更好的方法来实现快速I/O; 如何提高Rust中文件I/O的性能?
$ rustc --version
rustc 1.16.0
$ rustc rswrite.rs -C opt-level=3 # Rust for writing
$ time ./rswrite
real 1m8.411s
user 0m3.817s
sys 1m4.533s
$ rustc rsread.rs -C opt-level=3 # Rust for reading
$ time ./rsread
real 0m18.077s
user 0m2.130s
sys 0m15.910s
$ gcc -O3 cwrite.c -ocwrite # C for writing
$ time ./cwrite
real 0m1.564s
user 0m1.397s
sys 0m0.143s
$ gcc -O3 cread.c -ocread # C for reading
$ time ./cread
real 0m1.353s
user 0m1.240s
sys 0m0.113s
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写作的Rust代码:
use std::fs;
use std::io::Write;
fn main() {
let b = b"test";
let mut f = fs::File::create("rs.dump").unwrap();
for _ in 0 .. 100_000_000 {
f.write(b).unwrap();
}
}
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阅读的Rust代码:
use std::{fs, mem};
use std::io::Read;
fn main() {
let mut f = fs::File::open("rs.dump").unwrap();
let mut b: [u8; 4] = unsafe { mem::uninitialized() };
for _ in 0 .. 100_000_000 {
f.read_exact(&mut b).unwrap();
}
}
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写作的C代码:
#include <stdio.h>
#define N 100000000
int main()
{
const char *teststr = "test";
FILE *fp = fopen("c.dump", "wb");
unsigned long long i;
for (i=0; i<N; i++) fwrite(teststr, 4, 1, fp);
fclose(fp);
return 0;
}
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阅读的C代码:
#include <stdio.h>
#define N 100000000
int main() {
FILE *fp = fopen("c.dump", "rb");
long long i;
char buf[4];
for (i=0; i<N; i++) fread(buf, 4, 1, fp);
fclose(fp);
return 0;
}
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gyu*_*don 17
我的Rust程序没有使用缓冲IO.感谢BurntSushi5和Andrew Henle的评论,问题解决了.
$ strace ./rswrite
write(3, "test", 4) = 4
write(3, "test", 4) = 4
...
$ strace ./rswrite
read(3, "test", 4) = 4
read(3, "test", 4) = 4
...
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我修改了代码:
use std::fs;
use std::io::{BufWriter, Write};
fn main() {
let b = b"test";
/**** Use std::io::BufWriter ****/
let mut f = BufWriter::new(fs::File::create("rs.dump").unwrap());
for _ in 0 .. 100_000_000 {
f.write(b).unwrap();
}
}
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和
use std::{fs, mem};
use std::io::{BufReader, Read};
fn main() {
/**** Use std::io::BufReader ****/
let mut f = BufReader::new(fs::File::open("rs.dump").unwrap());
let mut b: [u8; 4] = unsafe { mem::uninitialized() };
for _ in 0 .. 100_000_000 {
f.read_exact(&mut b).unwrap();
}
}
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现在,I/O被缓冲了.
write(3, "testtesttesttesttesttesttesttest"..., 8192) = 8192
write(3, "testtesttesttesttesttesttesttest"..., 8192) = 8192
...
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性能和C一样快.
$ time ./rswrite
real 0m1.341s
user 0m0.213s
sys 0m0.200s
$ time ./rsread_buf
real 0m0.596s
user 0m0.540s
sys 0m0.050s
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