css选择器排除某些后代及其jquery对象的后代？

Question

给定一个具有多个级别后代的jquery对象,如何排除某些后代及其后代？假设.foo在要排除的元素的顶部节点上有一个类(在本例中),您的jquery对象div1如下所示.

编辑:澄清:我想排除所有后代,.foo而不仅仅是直接的孩子.

$('#button1').click(function() {
  var selector = '#test ' + $('#input1').val();
  var numberElements = $(selector).length;
  $('#numberElements').text(numberElements);
  var elementsAsCommaSeparatedList = _.pluck($(selector), 'id');
  $('#elementList').text(elementsAsCommaSeparatedList.join(', '));
});

#input1 {
  width: 230px;
  font-size: 16px;
  font-weight: bold;
}

#numberElements,
#elementList {
  color: green;
  font-weight: bold;
  font-size: 20px;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<label for="input1">Please supply a selector... $('<input id="input1" value="div:not(.foo, .foo *)"></label>')
<button id="button1">Apply Selector</button>
<div>(default value is from @DaniP's answer)</div>
<div id="result"><span>Number of elements selected:  </span><span id="numberElements">0</span></div>
<div>
  <span>Elements selected (by id):</span>
  <span id="elementList"></span>
</div>
<div id="test">
  <div id="div1">
    <div id="div2">
      <div id="div4">
        <div id="div8"></div>
        <div id="div9"></div>
      </div>
      <div id="div5" class="foo">
        <div id="div10"></div>
        <div id="div11"></div>
      </div>
    </div>
    <div id="div3">
      <div id="div6">
        <div id="div12"></div>
        <div id="div13"></div>
      </div>
      <div id="div7" class="foo">
        <div id="div14"></div>
        <div id="div15"></div>
      </div>
    </div>
  </div>
</div>

Answer 1

JQuery的

使用Jquery,您可以在:not选择器上使用多个参数,这样很容易排除.foo和子元素:

$('div:not(.foo, .foo *)')

_{示例代码段}

$('div:not(.foo, .foo *)').css('border-color','blue')

div {
  padding-left:20px;
  margin:5px;
  border:thin red solid;
}
.foo {
  background:rgba(0,0,0,.1)
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
DIV1
  <div>
  DIV2
    <div>
    DIV4
      <div>DIV8</div>
      <div>DIV9</div>
    </div>
    <div class="foo">
    DIV5
      <div>DIV10</div>
      <div>DIV11</div>
    </div>
  </div>
  <div>
  DIV3
    <div>
    DIV6
      <div>DIV12</div>
      <div>DIV13</div>
    </div>
    <div class="foo">
    DIV7
      <div>DIV14</div>
      <div>DIV15</div>
    </div>
  </div>
</div>

但是CSS不允许这样做,请参考这个答案.

CSS

在CSS上,你需要定位所有不是.foo但也会重写以下子元素的div .foo:

div:not(.foo) {
  border-color:blue;
}
div.foo * {
  border-color:red;
}

_{示例代码段}

div {
  padding-left:20px;
  margin:5px;
  border:thin red solid;
}
.foo {
  background:rgba(0,0,0,.1)
}
div:not(.foo) {
  border-color:blue;
}
div.foo * {
  border-color:red;
}

<div>
DIV1
  <div>
  DIV2
    <div>
    DIV4
      <div>DIV8</div>
      <div>DIV9</div>
    </div>
    <div class="foo">
    DIV5
      <div>DIV10</div>
      <div>DIV11</div>
    </div>
  </div>
  <div>
  DIV3
    <div>
    DIV6
      <div>DIV12</div>
      <div>DIV13</div>
    </div>
    <div class="foo">
    DIV7
      <div>DIV14</div>
      <div>DIV15</div>
    </div>
  </div>
</div>