stu*_*ubs 1 sql-server sorting clustered-index
这个有点困惑.我的印象是,如果没有给出ORDER BY,SELECT应默认为Clustered Index进行排序.
但是如果我运行下面的代码,它会使用NON-Clustered索引.
DROP TABLE TEST_TABLE
if NOT EXISTS(select 1 from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'TEST_TABLE')
BEGIN
CREATE TABLE TEST_TABLE (
[ID] int NOT NULL IDENTITY(1,1),
[col1] int NOT NULL,
[col2] int NOT NULL
CONSTRAINT [PK_TEST_TABLE] PRIMARY KEY CLUSTERED
(
[ID] ASC
)WITH (FILLFACTOR = 90) ON [PRIMARY]
) ON [PRIMARY]
END
IF EXISTS (SELECT * FROM sys.indexes WHERE object_id = OBJECT_ID(N'[dbo].[TEST_TABLE]') AND name = N'TEST_TABLE_cols')
DROP INDEX [TEST_TABLE_cols] ON [dbo].[TEST_TABLE]
CREATE UNIQUE NONCLUSTERED INDEX [TEST_TABLE_cols] ON [dbo].[TEST_TABLE]
( [col1] ASC,
[col2] ASC
)WITH (FILLFACTOR = 60) ON [PRIMARY];
GO
--GO
EXEC ('insert into test_table select 1, 0')
EXEC ('insert into test_table select 2, 0')
EXEC ('insert into test_table select 10, 0')
EXEC ('insert into test_table select 9, 0')
EXEC ('insert into test_table select 8, 0')
EXEC ('insert into test_table select 6, 0')
EXEC ('insert into test_table select 7, 0')
EXEC ('insert into test_table select 5, 0')
EXEC ('insert into test_table select 3, 0')
EXEC ('insert into test_table select 4, 0')
select * from test_table
Run Code Online (Sandbox Code Playgroud)
结果如下......
ID col1 col2
----------- ----------- -----------
1 1 0
2 2 0
9 3 0
10 4 0
8 5 0
6 6 0
7 7 0
5 8 0
4 9 0
3 10 0
Run Code Online (Sandbox Code Playgroud)
如果有人可以解释,将非常感谢!
我的印象是,如果没有给出ORDER BY,SELECT应默认为Clustered Index进行排序.
虽然在实践中可能看起来是这样的(如果行是简单的按顺序读取存储,这就是你得到的),在任何地方都没有这样的保证.查询或查询计划中的一个小变化很容易改变.
如果您未指定订单,则结果没有订单.
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