采用多列？

Question

当我使用多列的pluck时,我得到这个:

{"Kreis 1 \/ Altstadt":"City","Kreis 2":"Enge","Kreis 3":"Sihifeld","Kreis 4":"Hard","Kreis 5 \/ Industriequartier":"Escher Wyss","Kreis 6":"Oberstrass","Kreis 7":"Witikon","Kreis 8 \/ Reisbach":"Weinegg","Kreis 9":"Altstetten","Kreis 10":"Wipkingen","Kreis 11":"Seebach","Kreis 12 \/ Schwamendingen":"Hirzenbach"

但我需要这个吗？

["Rathaus","Hochschulen","Lindenhof","City","Wollishofen","Leimbach","Enge","Alt-Wiedikon","Friesenberg","Sihifeld","Werd","Langstrasse","Hard","Gewerbechule","Escher Wyss","Unterstrass","Oberstrass","Fluntern","Hottingen","Hirslanden","Witikon","Seefeld","M\u00fchlebach","Weinegg","Albisrieden","Altstetten","H\u00f6ngg","Wipkingen","Affoltern","Oerlikon","Seebach","Saatlen","Schwamendingen-Mitte","Hirzenbach"]

任何建议我怎么能这样做？这是我的方法:

    public function autocomplete_districts(Request $request)
   {
      $district = $request->input('query');
      // $ass = /DB::table('districts')->select(array('district', 'region'))->get();
      // dd($ass);
      $data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])->pluck('region','district');

      return response()->json($data);
   }

Answer 1

您应该使用select(),get()然后根据需要修改对象.

所以代替:->pluck('region','district'); 使用:->select('region','district')->get();

pluck() 当您只需要一列的值时,建议您使用.

并且尽可能地,你应该让你的模型单数形式而不是复数(区) - 遵循Laravel命名法.

Answer 2

就我而言，我想从 Eloquent 模型数组中提取 2 个值，这有效：

$models->map->only(['state', 'note'])->values()

这是较短的版本

$models->map(fn($model) => $model->only(['state', 'note']))->values()

Answer 3

这就是采弹的原理。而是尝试这个。

$data = Districts::whereRaw('LOWER(district) like ?', [strtolower('%'.$district . '%')])->orWhereRaw('LOWER(region) like ?', [strtolower('%'.$district . '%')])->select('region', 'district')->get();

$data = collect($data->toArray())->flatten()->all();

Answer 4

我在 LARAVEL 5.6 中的解决方案：

您好，我刚刚遇到了同样的问题，我需要将 2 列合并到 1 个选择列表中。我的数据库有 2 列用户：名字和姓氏。我需要一个选择框，其中显示用户全名，并将 ID 作为值。这就是我使用 pluck() 方法修复它的方法：

在用户模型中，我创建了一个全名访问器函数：

public function getNameAttribute() {
    return ucwords($this->last_name . ' ' . $this->first_name);
}

之后，为了使用全名和相应的数据库 ID 作为值填充选择列表，我在返回视图的控制器中使用了此代码（不显示已存档的用户，但如果您愿意，您可以更改查询的开头，最重要的是 get() 和 pluck() 函数：

$users = User::whereNull('archived_at')
    ->orderBy('last_name')
    ->get(['id','first_name','last_name'])
    ->pluck('name','id');
return view('your.view', compact('users'));

现在您可以在选择列表中使用 $users 了！

因此，首先，您从数据库中获取所需的所有值，之后您可以使用定义在 PLUCK 方法中使用的任何访问器属性，

只要访问器所需的所有列都在 GET 中即可；-)

Answer 5

这是我经常遇到的一个问题，并促使我创建了以下可用于模型或阵列的解决方案。
还支持点语法，可根据需要创建多维数组。

在AppServiceProvider（或您选择的任何提供程序）中注册此宏：

use Illuminate\Support\Arr;

/**
* Similar to pluck, with the exception that it can 'pluck' more than one column.
* This method can be used on either Eloquent models or arrays.
* @param string|array $cols Set the columns to be selected.
* @return Collection A new collection consisting of only the specified columns.
*/
Collection::macro('pick', function ($cols = ['*']) {
    $cols = is_array($cols) ? $cols : func_get_args();
    $obj = clone $this;

    // Just return the entire collection if the asterisk is found.
    if (in_array('*', $cols)) {
        return $this;
    }

    return $obj->transform(function ($value) use ($cols) {
        $ret = [];
        foreach ($cols as $col) {
            // This will enable us to treat the column as a if it is a
            // database query in order to rename our column.
            $name = $col;
            if (preg_match('/(.*) as (.*)/i', $col, $matches)) {
                $col = $matches[1];
                $name = $matches[2];
            }

            // If we use the asterisk then it will assign that as a key,
            // but that is almost certainly **not** what the user
            // intends to do.
            $name = str_replace('.*.', '.', $name);

            // We do it this way so that we can utilise the dot notation
            // to set and get the data.
            Arr::set($ret, $name, data_get($value, $col));
        }

        return $ret;
    });
});

然后可以通过以下方式使用它：

$a = collect([
    ['first' => 1, 'second' => 2, 'third' => 3],
    ['first' => 1, 'second' => 2, 'third' => 3]
]);

$b = $a->pick('first', 'third'); // returns [['first' => 1, 'third' => 3], ['first' => 1, 'third' => 3]]

或者另外，在您可能拥有的任何型号上：

$users = User::all();
$new = $users->pick('name', 'username', 'email');
// Might return something like:
// [
//     ['name' => 'John Doe', 'username' => 'john', 'email' => 'john@email.com'],
//     ['name' => 'Jane Doe', 'username' => 'jane', 'email' => 'jane@email.com'],
//     ['name' => 'Joe Bloggs', 'username' => 'joe', 'email' => 'joe@email.com'],
// ]

也可以使用点表示法以及使用as [other name]语法来引用任何关系：

$users = User::all();
$new = $users->pick('name as fullname', 'email', 'posts.comments');
// Might return something like:
// [
//     ['fullname' => 'John Doe', 'email' => 'john@email.com', 'posts' => [...]],
//     ['fullname' => 'Jane Doe', 'email' => 'jane@email.com', 'posts' => [...]],
//     ['fullname' => 'Joe Bloggs', 'email' => 'joe@email.com', 'posts' => [...]],
// ]