kwh*_*let 3 php database joomla
我正在编写一个脚本,它将作为cronjob运行,使用joomla数据库中的值进行一些计算,因为这个脚本不会通过joomla作为插件等访问,我需要与它进行数据库连接.
尝试做的是使用Joomla框架来完成所有工作(连接,查询等)以实现安全性和可移植性目的(而不是在此脚本中使用另一组登录凭据,它们全部由Joomla配置处理)
我已经做到了最好,但是当我运行脚本时,我收到以下错误:
Database Error: Unable to connect to the database:Could not connect to MySQL
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我打印出变量并确保mysql的连接细节是正确的(它们是).
我目前的守则是:
<?php
//init Joomla Framework
define( '_JEXEC', 1 );
define( 'JPATH_BASE', realpath(dirname(__FILE__).'/..' ));
define( 'DS', DIRECTORY_SEPARATOR );
require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' );
require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' );
require_once( JPATH_CONFIGURATION .DS.'configuration.php' );
require_once ( JPATH_BASE .DS.'includes'.DS.'database.php' );
require_once ( JPATH_LIBRARIES .DS.'joomla'.DS.'import.php' );
//DB Connection
$Config = new JConfig();
$option['driver'] = $Config->dbtype; // Database driver name
$option['host'] = $Config->host; // Database host name
$option['user'] = $Config->user; // User for database authentication
$option['password'] = $Config->password; // Password for database authentication
$option['database'] = $Config->db; // Database name
$option['prefix'] = $Config->dbprefix; // Database prefix (may be empty)
$db = & JDatabase::getInstance($option);
//DBQuery
$database =& JFactory::getDBO();
$query = "SELECT * FROM #__chronoforms_RD_NonDangerousGoods WHERE cf_id = 4;";
$database->setQuery($query);
$result = $database->query();
print_r($result);
?>
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小智 6
试试这个
<?php
//init Joomla Framework
define( '_JEXEC', 1 );
define( 'DS', DIRECTORY_SEPARATOR );
define( 'JPATH_BASE', realpath(dirname(__FILE__).DS.'..' ));
require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' );
require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' );
$mainframe = JFactory::getApplication('site');
//DBQuery
$database =& JFactory::getDBO();
$query = "SELECT * FROM #__chronoforms_RD_NonDangerousGoods WHERE cf_id = 4;";
$database->setQuery($query);
$result = $database->query();
print_r($result);
?>
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