如何基于ServiceInfo对象启动服务？

Question

在我的应用程序中,我查询其intent-filters中具有特定类别的服务列表.这很好,我得到一个包含ResolveInfo对象的List.在这些ResolveInfos中,我找到了"serviceInfo"字段,该字段应该描述找到的服务的详细信息.

现在我如何从serviceInfo构造一个Intent,它可以启动找到的服务？

我的代码现在是这样的:

PackageManager pm = getApplicationContext().getPackageManager();
  Intent i = new Intent();
  i.setAction("<my custom action>");
  i.addCategory("<my custom category>");

  List<ResolveInfo> l = pm.queryIntentServices(i, 0);

  gatherAgentNum = l.size();

  if(gatherAgentNum > 0){
   for(ResolveInfo info : l){
    Intent i2 = new Intent(this, info.serviceInfo.getClass());
    i2.putExtra(BaseAgent.KEY_RESULT_RECEIVER, new GatherResult(mHandler));
    startService(i2);
   }
  }

这显然是错误的,"info.serviceInfo.getClass()"只返回serviceInfo对象的类.任何人都可以帮我这个吗？

谢谢

编辑:解决方案(至少我使用的那个):

PackageManager pm = getApplicationContext().getPackageManager();
        Intent i = new Intent();
        i.setAction("<my action>");
        i.addCategory("<my category>");

        List<ResolveInfo> l = pm.queryIntentServices(i, 0);

        if(l.size() > 0){
            for(ResolveInfo info : l){
                ServiceInfo servInfo = info.serviceInfo;
                ComponentName name = new ComponentName(servInfo.applicationInfo.packageName, servInfo.name);

                Intent i2 = new Intent();
                i2.setComponent(name);

                startService(i2);
            }
        }

Answer 1

您是否看过：

• http://developer.android.com/reference/android/content/pm/ServiceInfo.html
• http://developer.android.com/reference/android/content/pm/PackageItemInfo.html#packageName
• http://developer.android.com/reference/android/content/pm/ApplicationInfo.html

.packageName我想你可以尝试用-替换 getClass 类并使用packageManager.getLaunchIntentForPackage(String)

另请看一下：

• http://developer.android.com/reference/android/content/pm/PackageManager.html
• queryIntentServices,resolveService