将MYSQL表导出为ex​​cel

Question

我有一些PHP脚本用于将MYSQL表导出为Excel格式,但是在导出表后我遇到了一些问题.从db获取的数据只显示一行.

这个脚本如下:

$dbc=mysql_connect(_SRV,_ACCID,_PWD) or die(_ERROR15.": ".mysql_error());
$db=mysql_select_db("qdbase",$dbc) or die(_ERROR17.": ".mysql_error());

$sQuery = "SELECT id, Line, Model,Lot_no,
                  COUNT( Serial_number ) AS Qty,
                  SUM(S), SUM(A), SUM(B), SUM(C),
                  (SUM(S) + SUM(A) + SUM(B)*0.4 + SUM(C)*0.1) / COUNT(Serial_number) AS QP,
                  ROUND((SUM(S) + SUM(A) + SUM(B)*0.4 + SUM(C)*0.1) / COUNT(Serial_number)*1000,2) AS PPM
            FROM  `inspection_report`";

$rResult = mysql_query( $sQuery) or die();
$count = mysql_num_fields($rResult);

// fetch table header
$header = '';
for ($i = 0; $i < $count; $i++){
       $header .= mysql_field_name($rResult, $i)."\t";
       }
// fetch data each row, store on tabular row data
while($row = mysql_fetch_row($rResult)){
       $line = '';
       foreach($row as $value){
              if(!isset($value) || $value == ""){
                     $value = "\t";
              }else{
                     $value = str_replace('"', '""', $value);
                     $value = '"' . $value . '"' . "\t";
                     }
              $line .= $value;
              }
       $data .= trim($line)."\n";
       $data = str_replace("\r", "", $data);

if ($data == "") {
       $data = "\nno matching records found\n";
       }

header("Content-type: application/vnd.ms-excel; name='excel'");
header("Content-Disposition: attachment; filename=exportfile.xls");
header("Pragma: no-cache");
header("Expires: 0");

// output data
echo $header."\n".$data;
?>

除此之外,如何为这张桌子做一些边框？

Answer 1

如果我想这样做:echo""; 哪个正确的位置使它不能使我的脚本成为错误？

如果你想把它做成一个html表,那么我会jsut输出谎言你通常对一个表...例如你可能会这样做:

$rResult = mysql_query( $sQuery) or die();
$count = mysql_num_fields($rResult);

$html = '<table border="1"><thead><tr>%s</tr><thead><tbody>%s</tbody></table>';
$thead = '';
$tbody = '';
$line = '<tr>%s</tr>';
for ($i = 0; $i < $count; $i++){      
  $thead .= sprintf('<th>%s</th>',mysql_field_name($rResult, $i));
}


while(false !== ($row = mysql_fetch_row($rResult))){
  $trow = '';

  foreach($row as $value){
   $trow .= sprintf('<td>%s</td>', $value);
  }

  $tbody .= sprintf($line, $trow);

}


header("Content-type: application/vnd.ms-excel; name='excel'");
header("Content-Disposition: attachment; filename=exportfile.xls");
header("Pragma: no-cache");
header("Expires: 0");

print sprintf($html, $thead, $tbody);
exit;

您只获得一行,因为您使用的是没有GROUP BY子句的聚合函数.尝试添加一个GROUP BY将这些"条目"中的每一个与某个特定组相关联的内容,例如Lot_no您尝试报告的内容.

至于边界,你不能这样做CSV虽然Excel虽然readbale,实际上并不是一个Excel格式文件与所有额外的东西,如边框格式.要使用格式化等内容,您需要输出本机Excel或可以加载到Excel中的html表.看看phpexcel你是否需要这样做.