rod*_*dbv 15 .net c# calendar gregorian-calendar week-number
根据官方(格里高利)日历,2008年12月29日的周数为1,因为在第52周的最后一天(即28/12)之后,该年剩下三天或更少的天数.有点奇怪,但没关系,规则是规则.
因此,根据这个日历,我们有2008/2009年的这些边界值
C#提供了一个GregorianCalendar类,它有一个函数GetWeekOfYear(date, rule, firstDayOfWeek).
该参数rule是一个包含3个可能值的枚举:FirstDay, FirstFourWeekDay, FirstFullWeek.根据我的理解,我应该FirstFourWeekDay遵守规则,但我尝试了所有这些以防万一.
最后一个参数通知哪个工作日应该被视为一周的第一天,根据该日历,它是星期一,所以它是星期一.
所以我启动了一个快速而肮脏的控制台应用程序来测试这个:
using System;
using System.Globalization;
namespace CalendarTest
{
class Program
{
static void Main(string[] args)
{
var cal = new GregorianCalendar();
var firstWeekDay = DayOfWeek.Monday;
var twentyEighth = new DateTime(2008, 12, 28);
var twentyNinth = new DateTime(2008, 12, 29);
var firstJan = new DateTime(2009, 1, 1);
var eightJan = new DateTime(2009, 1, 8);
PrintWeekDays(cal, twentyEighth, firstWeekDay);
PrintWeekDays(cal, twentyNinth, firstWeekDay);
PrintWeekDays(cal, firstJan, firstWeekDay);
PrintWeekDays(cal, eightJan, firstWeekDay);
Console.ReadKey();
}
private static void PrintWeekDays(Calendar cal, DateTime dt, DayOfWeek firstWeekDay)
{
Console.WriteLine("Testing for " + dt.ToShortDateString());
Console.WriteLine("--------------------------------------------");
Console.Write(CalendarWeekRule.FirstDay.ToString() + "\t\t");
Console.WriteLine(cal.GetWeekOfYear(dt, CalendarWeekRule.FirstDay, firstWeekDay));
Console.Write(CalendarWeekRule.FirstFourDayWeek.ToString() + "\t");
Console.WriteLine(cal.GetWeekOfYear(dt, CalendarWeekRule.FirstFourDayWeek, firstWeekDay));
Console.Write(CalendarWeekRule.FirstFullWeek.ToString() + "\t\t");
Console.WriteLine(cal.GetWeekOfYear(dt, CalendarWeekRule.FirstFullWeek, firstWeekDay));
Console.WriteLine("--------------------------------------------");
}
}
}
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......这就是我得到的
Testing for 28.12.2008
--------------------------------------------
FirstDay 52
FirstFourDayWeek 52
FirstFullWeek 51
--------------------------------------------
Testing for 29.12.2008
--------------------------------------------
FirstDay 53
FirstFourDayWeek 53
FirstFullWeek 52
--------------------------------------------
Testing for 01.01.2009
--------------------------------------------
FirstDay 1
FirstFourDayWeek 1
FirstFullWeek 52
--------------------------------------------
Testing for 08.01.2009
--------------------------------------------
FirstDay 2
FirstFourDayWeek 2
FirstFullWeek 1
--------------------------------------------
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因此,正如我们所看到的,上面的组合都没有与官方日历相匹配(如果你匆忙,只看到29/12从未得到第1周).
我在这里弄错了什么?也许有些东西明显让我失踪?(这是比利时的星期五和晚上的工作时间,请耐心等待;))
编辑:也许我应该解释一下:我需要的是一个适用于任何年份的函数,返回与我链接的格里高利历相同的结果.因此,2008年没有特别的解决方法.