scn*_*iro 11 javascript reactjs react-router react-router-v4
世界上如何在react-router中使用嵌套路由,特别是版本4.x?以下版本在以下版本中运行良好...
<Route path='/stuff' component={Stuff}>
<Route path='/stuff/a' component={StuffA} />
</Route>
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升级到4.x会发出以下警告......
警告:您不应在同一路径中使用<Route>组件和<Route children>; <Route children>将被忽略
到底发生了什么事?我已经搜索了几个小时的文档,无法成功地使嵌套路由工作.如何使用<Route>组件在react-router v4中嵌套其路由?我的简单示例如何转换为嵌套路由的v4.x API合规性?
Tyl*_*nis 11
忘掉你对React Router <v4的了解.您通过字面嵌套来嵌套路线<Routes>.检查此示例.具体来说,请查看主题组件.您不会预先声明路线,而是在组件渲染时动态声明.
import React from 'react'
import {
BrowserRouter as Router,
Route,
Link
} from 'react-router-dom'
const BasicExample = () => (
<Router>
<div>
<ul>
<li><Link to="/">Home</Link></li>
<li><Link to="/about">About</Link></li>
<li><Link to="/topics">Topics</Link></li>
</ul>
<hr/>
<Route exact path="/" component={Home}/>
<Route path="/about" component={About}/>
<Route path="/topics" component={Topics}/>
</div>
</Router>
)
const Home = () => (
<div>
<h2>Home</h2>
</div>
)
const About = () => (
<div>
<h2>About</h2>
</div>
)
const Topics = ({ match }) => (
<div>
<h2>Topics</h2>
<ul>
<li>
<Link to={`${match.url}/rendering`}>
Rendering with React
</Link>
</li>
<li>
<Link to={`${match.url}/components`}>
Components
</Link>
</li>
<li>
<Link to={`${match.url}/props-v-state`}>
Props v. State
</Link>
</li>
</ul>
{/* NESTED ROUTES */}
<Route path={`${match.url}/:topicId`} component={Topic}/>
<Route exact path={match.url} render={() => (
<h3>Please select a topic.</h3>
)}/>
</div>
)
const Topic = ({ match }) => (
<div>
<h3>{match.params.topicId}</h3>
</div>
)
export default BasicExample
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