How to read a binary file into an array of bytes?

Question

我有一个二进制文件,我正在读取字节数组的集合.

该文件包含多个(任意数量)记录.本质上是一个字节块.每条记录都是任意长度的.

文件的标题提供每个记录的偏移量.

record 0: offset 2892
record 1: offset 4849
....
record 98: offset 328932
record 99: offset 338498

我编写了代码来循环并在每个记录中读取它的字节数组.查看偏移量的差异给出了记录大小.寻找偏移然后调用ReadBytes()将记录读入其数组.

我目前的不完整解决方案不适用于最后一条记录.你如何将最后一条记录读入数组(记住它是任意长度的).

至于为什么？每条记录都是加密的,需要单独解密.我正在编写代码,将每条记录读入一个字节数组.解密它然后将所有记录写回文件.

代码根据要求添加:

    //recordOffsets contain byte location of each record start.  All headers (other than universal header) are contained within record 0.
    recordBlocks = new List<RecordBlock>();

    //store all recordOffsets.  Record0 offset will be used to load rest of headers.  Remaining are used to parse text of eBook.
    for (int i = 0; i < standardHeader.numRecs; i++)
    {
        RecordBlock r = new RecordBlock();
        r.offset = bookReader.ReadInt32(EndianReader.Endian.BigEndian);
        r.number = bookReader.ReadInt32(EndianReader.Endian.BigEndian);
        recordBlocks.Add(r);
    }

    foreach (RecordBlock r in recordBlocks)
    {
        if (r.number  == recordBlocks.Count)
        {
            ///deal with last record
        }
        else
        {
            r.size = recordBlocks[(r.number) + 1].offset - r.offset;   
        }
        bookReader.Seek(r.offset, SeekOrigin.Begin);
        r.data = bookReader.ReadBytes(r.size);            
    }

Answer 1

System.IO.File.ReadAllBytes() 将读取字节数组中的所有字节,然后您可以按记录从该字节数组中读取.