laravel 5.4上传图片

Saw*_*wan 28 php laravel-5.4

我在laravel 5.4中上传文件的控制器代码:

if ($request->hasFile('input_img')) {
    if($request->file('input_img')->isValid()) {
        try {
            $file = $request->file('input_img');
            $name = rand(11111, 99999) . '.' . $file->getClientOriginalExtension();
            $request->file('input_img')->move("fotoupload", $name);
        } catch (Illuminate\Filesystem\FileNotFoundException $e) {

        }
    }
}
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图像已成功上传,但代码引发了异常:

MimeTypeGuesser.php第123行中的FileNotFoundException

该文件在我的代码中有任何错误,或者它是laravel 5.4中的错误,任何人都可以帮我解决问题吗?

我的观点代码:

<form enctype="multipart/form-data" method="post" action="{{url('admin/post/insert')}}">
    {{ csrf_field() }}
    <div class="form-group">
        <label for="imageInput">File input</label>
        <input data-preview="#preview" name="input_img" type="file" id="imageInput">
        <img class="col-sm-6" id="preview"  src="">
        <p class="help-block">Example block-level help text here.</p>
    </div>
    <div class="form-group">
        <label for="">submit</label>
        <input class="form-control" type="submit">
    </div>
</form>
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小智 37

试试这个代码.这将解决您的问题.

public function fileUpload(Request $request) {
    $this->validate($request, [
        'input_img' => 'required|image|mimes:jpeg,png,jpg,gif,svg|max:2048',
    ]);

    if ($request->hasFile('input_img')) {
        $image = $request->file('input_img');
        $name = time().'.'.$image->getClientOriginalExtension();
        $destinationPath = public_path('/images');
        $image->move($destinationPath, $name);
        $this->save();

        return back()->with('success','Image Upload successfully');
    }
}
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  • 我喜欢这个,它增加了验证。 (2认同)

小智 21

您可以通过store控制器中的方法轻松地使用它

如下所示

首先,我们必须创建一个带有文件输入的表单,让我们上传我们的文件.

{{Form::open(['route' => 'user.store', 'files' => true])}}

{{Form::label('user_photo', 'User Photo',['class' => 'control-label'])}}
{{Form::file('user_photo')}}
{{Form::submit('Save', ['class' => 'btn btn-success'])}}

{{Form::close()}}
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以下是我们如何处理控制器中的文件.

<?php

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use App\Http\Controllers\Controller;

class UserController extends Controller
{

  public function store(Request $request)
  {

  // get current time and append the upload file extension to it,
  // then put that name to $photoName variable.
  $photoName = time().'.'.$request->user_photo->getClientOriginalExtension();

  /*
  talk the select file and move it public directory and make avatars
  folder if doesn't exsit then give it that unique name.
  */
  $request->user_photo->move(public_path('avatars'), $photoName);

  }
}
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而已.现在,您可以将数据保存$photoNameuser_photo字段值.您可以asset(‘avatars’)在视图中使用功能并访问照片.


小智 7

您的应用程序的一个好的逻辑可能是这样的:

 public function uploadGalery(Request $request){
      $this->validate($request, [
        'file' => 'required|image|mimes:jpeg,png,jpg,bmp,gif,svg|max:2048',
      ]);
      if ($request->hasFile('file')) {
        $image = $request->file('file');
        $name = time().'.'.$image->getClientOriginalExtension();
        $destinationPath = public_path('/storage/galeryImages/');
        $image->move($destinationPath, $name);
        $this->save();
        return back()->with('success','Image Upload successfully');
      }

    }
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小智 5

使用以下代码:

$imageName = time().'.'.$request->input_img->getClientOriginalExtension();
$request->input_img->move(public_path('fotoupload'), $imageName);
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  • 您应该尝试提供解释和代码。 (4认同)

小智 1

if ($request->hasFile('input_img')) {
    if($request->file('input_img')->isValid()) {
        try {
            $file = $request->file('input_img');
            $name = time() . '.' . $file->getClientOriginalExtension();

            $request->file('input_img')->move("fotoupload", $name);
        } catch (Illuminate\Filesystem\FileNotFoundException $e) {

        }
    } 
}
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或关注
https://laracasts.com/discuss/channels/laravel/image-upload-file-does-not-working

https://laracasts.com/series/whats-new-in-laravel-5-3/集/12