sto*_*ebe 3 python parsing geojson
我有一个查询的geojson数据,我现在想在屏幕上解析和打印.我目前的代码是:
import urllib
import geojson
while True:
url = 'https://earthquake.usgs.gov/fdsnws/event/1/query?format=geojson&starttime=2012-01-01&endtime=2017-03-01&minmagnitude=4.0&maxmagnitude=9.0&minlongitude=5.95&maxlongitude=10.50&minlatitude=45.81&maxlatitude=47.81'
uh = urllib.urlopen(url)
data = uh.read()
print data
break
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看来这data是一个简单的字符串.但是,我认为它可以像json参数一样进行解析.我如何处理geojson数据以打印单个数据point,例如仅提取第一个点的坐标?
小智 29
import geojson
with open(path_to_file) as f:
gj = geojson.load(f)
features = gj['features'][0]
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sag*_*arr 11
您还可以使用geopandas:
import geopandas as gpd
earthquake = gpd.read_file('earthquake.geojson')
print(earthquake.head())
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你可以像任何json一样阅读它:
import json
data = json.loads(datastring)
data['features'][0]['geometry'] #Your first point
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您可以使用 json 导入来读取它,然后打开文件:
import json
with open(path) as f:
data = json.load(f)
for feature in data['features']:
print(feature['properties'])
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