如何在jenkins管道中抛出异常？

Question

我用try catch块处理了Jenkins管道步骤.我想在某些情况下手动抛出异常.但它显示以下错误.

org.jenkinsci.plugins.scriptsecurity.sandbox.RejectedAccessException: Scripts not permitted to use new java.io.IOException java.lang.String

我检查了scriptApproval部分,没有待批准的批准.

Answer 1

如果要在异常时中止程序,可以使用管道步骤error来停止管道执行并显示错误.示例:

try {
  // Some pipeline code
} catch(Exception e) {
   // Do something with the exception 

   error "Program failed, please read logs..."
}

如果要以成功状态停止管道,可能需要某种布尔值来指示必须停止管道,例如:

boolean continuePipeline = true
try {
  // Some pipeline code
} catch(Exception e) {
   // Do something with the exception 

   continuePipeline = false
   currentBuild.result = 'SUCCESS'
}

if(continuePipeline) {
   // The normal end of your pipeline if exception is not caught. 
}

Answer 2

这就是我在Jenkins 2.x中的做法。

注意：不要使用错误信号，它会跳过所有发布步骤。

stage('stage name') {
            steps {
                script {
                    def status = someFunc() 

                    if (status != 0) {
                        // Use SUCCESS FAILURE or ABORTED
                        currentBuild.result = "FAILURE"
                        throw new Exception("Throw to stop pipeline")
                        // do not use the following, as it does not trigger post steps (i.e. the failure step)
                        // error "your reason here"

                    }
                }
            }
            post {
                success {
                    script {
                        echo "success"
                    }
                }
                failure {
                    script {
                        echo "failure"
                    }
                }
            }            
        }

Answer 3

似乎没有其他异常Exception可以抛出。不IOException，不RuntimeException，等等。

这将起作用：

throw new Exception("Something went wrong!")

但是这些不会：

throw new IOException("Something went wrong!")
throw new RuntimeException("Something went wrong!")