我试图找到一个文件的存在,然后在命令提示符下打印出如下目录:
C:\> if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo C:\Program Files(x86)\Microsoft Visual Studio 14.0\)
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这失败并出现以下错误:
\Microsoft was unexpected at this time.
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如果我重写我的命令
C:\> if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo "C:\Program Files(x86)\Microsoft Visual Studio 14.0\")
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这打印:
"C:\Program Files(x86)\Microsoft Visual Studio 14.0\"
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我使用了这个命令的输出,并且它周围的引号引起了一些问题.有什么办法可以在不添加引号的情况下回应这个问题吗?
问题是该echo
部分的括号,结束)
时(x86)
被认为是(
前面开口的对应部分echo
.
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo C:\Program Files(x86)\Microsoft Visual Studio 14.0\)
rem // ^ ^
rem // +opening-----------closing+
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所以你有两个选择:
要么删除(
/ )
围绕整个echo
命令行:
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" echo C:\Program Files(x86)\Microsoft Visual Studio 14.0\
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,如:
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo C:\Program Files^(x86^)\Microsoft Visual Studio 14.0\)
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要么:
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo C:\Program Files(x86^)\Microsoft Visual Studio 14.0\)
Run Code Online (Sandbox Code Playgroud)条件命令部分周围的括号不是必需的,除非:
你想建立一个多线块:
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (
echo C:\Program Files^(x86^)\Microsoft Visual Studio 14.0\
)
Run Code Online (Sandbox Code Playgroud)或者你想使用这个else
条款:
if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (echo C:\Program Files^(x86^)\Microsoft Visual Studio 14.0\) else echo ERROR: file not found!
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if exist "C:\Program Files(x86)\Microsoft Visual Studio 14.0\VC\vcvarsall.bat" (
echo C:\Program Files^(x86^)\Microsoft Visual Studio 14.0\
) else (
echo ERROR: file not found!
)
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