用多列拆分df的“ tidyverse”方法是什么?

Tie*_*nan 5 r purrr tidyverse

我想将数据框分成多列,以便可以看到summary()数据的每个子集的输出。

这是使用split()from 实现此目的的方法base

library(tidyverse)
#> Loading tidyverse: ggplot2
#> Loading tidyverse: tibble
#> Loading tidyverse: tidyr
#> Loading tidyverse: readr
#> Loading tidyverse: purrr
#> Loading tidyverse: dplyr
#> Conflicts with tidy packages ----------------------------------------------
#> filter(): dplyr, stats
#> lag():    dplyr, stats

mtcars %>% 
  select(1:3) %>% 
  mutate(GRP_A = sample(LETTERS[1:2], n(), replace = TRUE),
         GRP_B = sample(c(1:2), n(), replace = TRUE)) %>% 
  split(list(.$GRP_A, .$GRP_B)) %>% 
  map(summary)
#> $A.1
#>       mpg             cyl           disp          GRP_A          
#>  Min.   :10.40   Min.   :4.0   Min.   :108.0   Length:10         
#>  1st Qu.:14.97   1st Qu.:4.5   1st Qu.:151.9   Class :character  
#>  Median :18.50   Median :7.0   Median :259.3   Mode  :character  
#>  Mean   :17.61   Mean   :6.4   Mean   :283.4                     
#>  3rd Qu.:20.85   3rd Qu.:8.0   3rd Qu.:430.0                     
#>  Max.   :24.40   Max.   :8.0   Max.   :472.0                     
#>      GRP_B  
#>  Min.   :1  
#>  1st Qu.:1  
#>  Median :1  
#>  Mean   :1  
#>  3rd Qu.:1  
#>  Max.   :1  
#> 
#> $B.1
#>       mpg             cyl           disp          GRP_A          
#>  Min.   :15.00   Min.   :4.0   Min.   : 75.7   Length:5          
#>  1st Qu.:21.00   1st Qu.:4.0   1st Qu.: 78.7   Class :character  
#>  Median :21.50   Median :4.0   Median :120.1   Mode  :character  
#>  Mean   :24.06   Mean   :5.2   Mean   :147.1                     
#>  3rd Qu.:30.40   3rd Qu.:6.0   3rd Qu.:160.0                     
#>  Max.   :32.40   Max.   :8.0   Max.   :301.0                     
#>      GRP_B  
#>  Min.   :1  
#>  1st Qu.:1  
#>  Median :1  
#>  Mean   :1  
#>  3rd Qu.:1  
#>  Max.   :1  
#> 
#> $A.2
#>       mpg             cyl             disp          GRP_A          
#>  Min.   :15.20   Min.   :4.000   Min.   : 95.1   Length:9          
#>  1st Qu.:16.40   1st Qu.:6.000   1st Qu.:160.0   Class :character  
#>  Median :18.10   Median :8.000   Median :275.8   Mode  :character  
#>  Mean   :19.84   Mean   :6.667   Mean   :234.0                     
#>  3rd Qu.:21.00   3rd Qu.:8.000   3rd Qu.:275.8                     
#>  Max.   :30.40   Max.   :8.000   Max.   :360.0                     
#>      GRP_B  
#>  Min.   :2  
#>  1st Qu.:2  
#>  Median :2  
#>  Mean   :2  
#>  3rd Qu.:2  
#>  Max.   :2  
#> 
#> $B.2
#>       mpg             cyl         disp          GRP_A          
#>  Min.   :13.30   Min.   :4   Min.   : 71.1   Length:8          
#>  1st Qu.:14.97   1st Qu.:4   1st Qu.:125.3   Class :character  
#>  Median :20.55   Median :6   Median :201.5   Mode  :character  
#>  Mean   :20.99   Mean   :6   Mean   :213.5                     
#>  3rd Qu.:23.93   3rd Qu.:8   3rd Qu.:315.5                     
#>  Max.   :33.90   Max.   :8   Max.   :360.0                     
#>      GRP_B  
#>  Min.   :2  
#>  1st Qu.:2  
#>  Median :2  
#>  Mean   :2  
#>  3rd Qu.:2  
#>  Max.   :2
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如何使用tidyverse动词达到相同的结果?我最初的想法是使用purrr::by_slice(),但显然已经弃用了。

Mar*_*kum 7

dplyr 0.8.0 引入了您正在寻找的动词:group_split()

从文档中:

group_split() 的作用类似于base::split()但是

  • 它使用 group_by() 中的分组结构,因此受数据掩码的约束

  • 它不会根据分组命名列表的元素,因为这通常会丢失信息并且令人困惑。

group_keys()通过返回每个组一行和每个分组变量一列的数据帧来解释分组结构。

对于你的例子:

mtcars %>% 
  select(1:3) %>% 
  mutate(GRP_A = sample(LETTERS[1:2], n(), replace = TRUE),
         GRP_B = sample(c(1:2), n(), replace = TRUE)) %>% 
  group_split(GRP_A, GRP_B) %>% 
  map(summary)
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