Android Espresso：测试动态创建的未分配 ID 的按钮

Question

我有多个在 for 循环中动态创建的按钮，并且没有 ID。我需要对这些按钮进行自动化测试。我怎样才能用浓缩咖啡做到这一点？这是创建各种按钮的 for 循环：

 for (int i = 0; i < numberOfSamples; i++) {
            TableRow.LayoutParams vl = new TableRow.LayoutParams(30,30);
            Button b = new Button(context);
            b.setId(((blockNumber * 10000)+i));
            //b.setHint(i);
            //b.setHint(blockNumber);
    //      double selectedGrade = 0;
    //      if(FinalSurvey.multi[blockNumber][i] != 0){
    //          selectedGrade = FinalSurvey.multi[blockNumber][i];
    //      }
    //      final int makeHighlight = selectedGrade;
            b.setBackgroundDrawable(context.getResources().getDrawable(R.drawable.a));
            b.setAlpha(1.0f);
            b.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    ViewsAdding va = new ViewsAdding();
                    va.showGrades(context, v, grades);
                    view = v;
                    maincontext = context;
                }
            });

            if(i%5 == 0){
                innerLayout = new LinearLayout(context);
                innerLayout.setOrientation(LinearLayout.HORIZONTAL);
                innerLayout.setLayoutParams(innerparams);
                vl.setMargins(5, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else if (i%5 ==1) {
                vl.setMargins(22, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else if (i%5 ==2) {
                vl.setMargins(25, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                mainLinearLayout.addView(innerLayout);
                b = null;
            }else if (i%5 ==3) {
                innerLayout = new LinearLayout(context);
                innerLayout.setOrientation(LinearLayout.HORIZONTAL);
                innerLayout.setLayoutParams(innerparams);
                vl.setMargins(35, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                if(i == numberOfSamples-1){
                    mainLinearLayout.addView(innerLayout);
                }
                b = null;
            }else{
                vl.setMargins(30, 5, 5, 5);
                b.setLayoutParams(vl);
                innerLayout.addView(b);
                mainLinearLayout.addView(innerLayout);
                b = null;
            }
        }
        return mainLinearLayout;
    }

Answer 1

在创建按钮的代码中，根据情况向按钮添加标签：

button.setTag("someTag");

因此，在您的情况下，您可以在 if 子句中执行此操作：

       if(i%5 == 0){
            ...
            b.setTag("case0-" + i);
            ...
        }else if (i%5 ==1) {
            ...
            b.setTag("case1-" + i);
            ...
        }
        ...

然后在您的测试中您可以使用此按钮获取按钮或单击它：

onView(allOf(withTagValue(is((Object) "case0-0")), isDisplayed())).perform(click());
onView(allOf(withTagValue(is((Object) "case0-0")), isDisplayed())).perform(click());

您还可以用循环替换“case0-0”字符串来重新生成标签