SQLAlchemy:使用`和`和`或`时出现意外结果

Mar*_*aev 15 python boolean sqlalchemy

我有一个通过SQLAlchemy创建的数据库"新闻":

class News(Base):
    __tablename__ = "news"
    id = Column(Integer, primary_key = True)
    title = Column(String)
    author = Column(String)
    url = Column(String)
    comments = Column(Integer)
    points = Column(Integer)
    label = Column(String)
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我还有一个函数News,它获取一个字符串并返回3个字符串变体之一:'good','maybe'或'never'.我尝试过滤行:

rows = s.query(News).filter(News.label == None and f(News.title) == 'good').all()
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但是程序失败了,引发了这个错误:

raise TypeError("Boolean value of this clause is not defined")
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我该如何解决?

Ilj*_*ilä 28

问题是这样的:

News.label == None and f(News.title) == 'good'
#                  ^^^ here
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Python没有允许覆盖布尔的行为操作 andor.您可以__bool__在Python 3和__nonzero__Python 2中对它们进行某种程度的影响,但所有这一切都是它定义了对象的真值.

如果有问题的对象没有执行__bool__,并抛出的错误,或执行没有抛出,你就已经得到了可能是非常模糊的错误由于发生短路性质andor:

In [19]: (News.label == 'asdf') and True
Out[19]: <sqlalchemy.sql.elements.BinaryExpression object at 0x7f62c416fa58>

In [24]: (News.label == 'asdf') or True
Out[24]: True
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因为

In [26]: bool(News.label == 'asdf')
Out[26]: False
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这可能并且会以不正确的SQL表达式的形式导致头发拉动:

In [28]: print(News.label == 'asdf' or News.author == 'NOT WHAT YOU EXPECTED')
news.author = :author_1
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为了产生布尔SQL表达式要么使用and_(),or_()not_()SQL表达式的功能,或二进制&,|~操作者重载:

# Parentheses required due to operator precedence
filter((News.label == None) & (f(News.title) == 'good'))
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要么

filter(and_(News.label == None, f(News.title) == 'good'))
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或将多个标准传递给Query.filter():

filter(News.label == None, f(News.title) == 'good')
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或组合多个电话filter():

filter(News.label == None).filter(f(News.title) == 'good')
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