Jam*_*mad 1 laravel laravel-5.4
我是laravel的新手,我希望按用户ID获取用户的单个记录并在输入值中显示.请指导我
public function profile(){
$userdata = User::all();
return view('pages/edit-profile')->with('userdata',$userdata);
}
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Route::get('profile', 'PageController@profile_c');
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<form class="form-horizontal" role="form" action="/edit_profile" method="post">
{{ csrf_field() }}
<div class="form-group">
<label class="col-lg-3 control-label">First name:</label>
<div class="col-lg-8">
<input class="form-control" name="firstName" id="firstName" type="text" value="Jane">
</div>
</div>
<div class="form-group">
<label class="col-lg-3 control-label">Last name:</label>
<div class="col-lg-8">
<input class="form-control" name="lastName" id="lastName" type="text" value="Bishop">
</div>
</div>
<div class="form-group">
<label class="col-lg-3 control-label">Display name:</label>
<div class="col-lg-8">
<input class="form-control" name="displayName" id="displayName" type="text" value="Jane Bishop">
</div>
</div>
<div class="form-group">
<label class="col-lg-3 control-label">Email:</label>
<div class="col-lg-8">
<input class="form-control" name="email" id="email" disabled type="email" value="janesemail@gmail.com">
</div>
</div>
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通过他们的id获取用户
$user = User::find(id);
return view('pages/edit-profile', compact('user));
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如果您从用户那里了解其他与用户电子邮件类似的独特内容
$user = User::where('email', $email)->first();
return view('pages/edit-profile', compact('user));
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在表单中,如果您使用刀片
<input name="email" value={{ $user->email }} />
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更重要的是,如何使用ELoquent:https://laravel.com/docs/5.4/eloquent