Proxyquire不会截断我所需的课程

Dav*_*Sag 6 javascript unit-testing proxyquire es6-class

我有一个课AProvider要求'./b.provider'.

const BProvider = require('./b.provider');

class AProvider {
  static get defaultPath() {
    return `defaults/a/${BProvider.getThing()}`;
  }
}

module.exports = AProvider;
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b.provider.js毗邻a.provider.js并且看起来像

global.stuff.whatever = require('../models').get('Whatever'); // I didn't write this!

class BProvider {
  static getThing() {
    return 'some-computed-thing';
  }
}
module.exports = BProvider;
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在我的测试中,我使用如下proxyquire模拟./b.provider:

import { expect } from 'chai';
import proxyquire from 'proxyquire';

describe('A Provider', () => {
  const Provider = proxyquire('../src/a.provider', {
    './b.provider': {
      getThing: () => 'b-thing'
    },
  });

  describe('defaultPath', () => {
    it('has the expected value', () => {
      expect(Provider.defaultPath).to.equal('defaults/a/b-thing')
    });
  });
});
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但是,当我运行测试BProvider仍然需要实际'./b.provider'不是存根而BProvider的引用global.stuff.whatever是抛出错误.

为什么这不起作用?

Dav*_*Sag 5

关于为什么会发生这种情况的答案如下

proxyquire在将其删除之前仍然需要底层代码.它这样做是为了启用呼叫.

解决方案只是明确禁止通过.

测试成为:

import { expect } from 'chai';
import proxyquire from 'proxyquire';

describe('A Provider', () => {
  const Provider = proxyquire('../src/a.provider', {
    './b.provider': {
      getThing: () => 'b-thing',
      '@noCallThru': true
    },
  });

  describe('defaultPath', () => {
    it('has the expected value', () => {
      expect(Provider.defaultPath).to.equal('defaults/a/b-thing')
    });
  });
});
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运行此测试非常有效.