Mik*_*ike 5 reactjs graphql react-redux react-apollo
我正在构建一个React前端,它允许用户从静态查询列表中选择"活动"查询,并展平到要在表格中显示的结果.将GraphQL查询从更高阶组件传递到嵌套子组件的最佳方法是什么?
我见过的大多数文档/解决方案都侧重于将动态条件从组件状态绑定到组件的静态查询,这对我的目的不起作用,因为不同的静态查询具有不同的字段并查询不同的节点类型.
这里的最佳实践/推荐方法是什么?我觉得这不是一个非常独特的用例,但我似乎找不到任何类似的例子.
我使用Apollo-Client/Redux作为我的客户端商店.
以下是组件的粗略轮廓:
class GridViewPage extends React.Component{
constructor(props, context) {
super(props, context);
this.state = {
activeQuery = ... Stores the selected query ...
};
}
render() {
return (
<div className="gridContainer">
...Component here allows users to select a query from active list and saves it/it's ID/Index to the state...
<Panel collapsible>
...Some toolbar components...
</Panel>
...Component here displays the result of the query (Ideally by receiving the query or the result of as a prop?)...
</div>
);
}
}
GridViewPage.propTypes = {
grids: PropTypes.array.isRequired,
actions: PropTypes.object.isRequired
};
function mapStateToProps(state, ownProps) {
return {
// Receives list of available queries as a prop
grids: state.grids
};
}Run Code Online (Sandbox Code Playgroud)
我们以以下组件为例:
ProfileWithData.js
import React, { Component, PropTypes } from 'react';
import { graphql } from 'react-apollo';
import gql from 'graphql-tag';
class Profile extends Component { ... }
Profile.propTypes = {
data: PropTypes.shape({
loading: PropTypes.bool.isRequired,
currentUser: PropTypes.object,
}).isRequired,
};
// We use the gql tag to parse our query string into a query document
const CurrentUserForLayout = gql`
query CurrentUserForLayout {
currentUser {
login
avatar_url
}
}
`;
const ProfileWithData = graphql(CurrentUserForLayout)(Profile);
Run Code Online (Sandbox Code Playgroud)
它可以很容易地用更高阶的组件包装它:
Profile.js
import React, { Component, PropTypes } from 'react';
export class Profile extends Component { ... }
Profile.propTypes = {
data: PropTypes.shape({
loading: PropTypes.bool.isRequired,
currentUser: PropTypes.object,
}).isRequired,
};
Run Code Online (Sandbox Code Playgroud)
createProfileWithData.js
import React, { Component, PropTypes } from 'react';
import { graphql } from 'react-apollo';
import { Profile } from './Profile'
export default function createProfileWithData(query) => {
return graphql(query)(Profile);
}
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然后你可以像这样使用它:
页面.js
import React, { Component, PropTypes } from 'react';
import gql from 'graphql-tag';
import createProfileWithData from './createProfileWithData';
class Page extends Component {
renderProfileWithData() {
const { textQuery } = this.props;
// Simplest way, though you can call gql as a function too
const graphQLQuery = gql`${textQuery}`;
const profileWithDataType = createProfileWithData(graphQLQuery);
return (
<profileWithDataType />
);
}
render() {
return (<div>
..
{this.renderProfileWithData()}
..
</div>)
}
}
Profile.propTypes = {
textQuery: PropTypes.string.isRequired,
};
Run Code Online (Sandbox Code Playgroud)
我认为你说对了。
当然,您的 Profile 不会收到props.data.currentUser,而是取决于props.data.*根查询,您将根据内容进行适当的处理。
注意:这是直接在 Stack Overflow 中编写的,因此如果您遇到任何问题 - lmk,我会修复它。