当我的编码没有设法选择要删除的项目的ID时,我不明白,我认为应该获得正确的ID.我使用下面的编码显示了我的所有项目.显示的每个项目都有自己的删除和编辑链接.
<?php
$sql_select = "SELECT * FROM tblproduct LEFT JOIN productcategory ON tblproduct.prodCat = productcategory.catID ORDER BY tblproduct.id DESC";
$result = $conn->query($sql_select);
if ($result->num_rows > 0){
while($row = mysqli_fetch_assoc($result))
{
?>
<li>
<h3><?php echo $row['prodName']; ?></h3>
<div>
<img src="<?php echo "user_images/".$row['prodImg']; ?>" />
</div>
<p>Code : <?php echo $row['prodCode']; ?></p>
<p>Price : RM<?php echo $row['prodPrice']; ?></p>
<p>Category : <?php echo $row['prodCat']; ?></p>
<p>Description : <?php echo $row['prodDesc']; ?></p>
<span>
<a class="btn btn-info" href="editform.php?edit_id=<?php echo $row['id']; ?>" title="click for edit" onclick="return confirm('sure to edit ?')"><span class="glyphicon glyphicon-edit"></span> Edit</a>
<a class="btn btn-danger" href="function.php?delete_id=<?php echo $row['id']; ?>" title="click for delete" onclick="return confirm('sure to delete ?')"><span class="glyphicon glyphicon-remove-circle"></span> Delete</a>
</span>
</li>
<?php
}
}
?>
Run Code Online (Sandbox Code Playgroud)
参考上面的代码,当我点击删除链接时,项目ID总是返回1,我的数据库只有两个 id从哪个记录开始17
列ID不明确,也可以来自productcategory.所以你需要做类似下面的事情
$sql_select = "SELECT tblproduct.id as product_id,* FROM tblproduct LEFT JOIN productcategory ON tblproduct.prodCat = productcategory.catID ORDER BY tblproduct.id DESC";
Run Code Online (Sandbox Code Playgroud)
HTML
<a class="btn btn-danger" href="function.php?delete_id=<?php echo $row['product_id']; ?>" title="click for delete" onclick="return confirm('sure to delete ?')"><span class="glyphicon glyphicon-remove-circle"></span> Delete</a>
</span>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
55 次 |
| 最近记录: |