在代码中,变量计时器将指定结束while循环的持续时间,例如60秒.
while(timer) {
//run
//terminate after 60 sec
}
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Mat*_*all 46
long start = System.currentTimeMillis();
long end = start + 60*1000; // 60 seconds * 1000 ms/sec
while (System.currentTimeMillis() < end)
{
// run
}
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d0x*_*d0x 23
您应该尝试新的Java Executor服务. http://docs.oracle.com/javase/6/docs/api/java/util/concurrent/ExecutorService.html
有了这个,你不需要自己编程循环时间.
public class Starter {
public static void main(final String[] args) {
final ExecutorService service = Executors.newSingleThreadExecutor();
try {
final Future<Object> f = service.submit(() -> {
// Do you long running calculation here
Thread.sleep(1337); // Simulate some delay
return "42";
});
System.out.println(f.get(1, TimeUnit.SECONDS));
} catch (final TimeoutException e) {
System.err.println("Calculation took to long");
} catch (final Exception e) {
throw new RuntimeException(e);
} finally {
service.shutdown();
}
}
}
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如果你不能超过你的时间限制(这是一个硬限制),那么线程是你最好的选择。一旦达到时间阈值,您可以使用循环来终止线程。当时该线程中发生的任何事情都可以被中断,从而使计算几乎立即停止。下面是一个例子:
Thread t = new Thread(myRunnable); // myRunnable does your calculations
long startTime = System.currentTimeMillis();
long endTime = startTime + 60000L;
t.start(); // Kick off calculations
while (System.currentTimeMillis() < endTime) {
// Still within time theshold, wait a little longer
try {
Thread.sleep(500L); // Sleep 1/2 second
} catch (InterruptedException e) {
// Someone woke us up during sleep, that's OK
}
}
t.interrupt(); // Tell the thread to stop
t.join(); // Wait for the thread to cleanup and finish
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这将使您的分辨率达到大约 1/2 秒。通过在 while 循环中更频繁地轮询,您可以解决这个问题。
你的 runnable 的运行看起来像这样:
public void run() {
while (true) {
try {
// Long running work
calculateMassOfUniverse();
} catch (InterruptedException e) {
// We were signaled, clean things up
cleanupStuff();
break; // Leave the loop, thread will exit
}
}
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根据 Dmitri 的回答进行更新
Dmitri 指出TimerTask,它可以让你避免循环。您可以只执行 join 调用,您设置的 TimerTask 将负责中断线程。这将使您获得更精确的分辨率,而无需循环轮询。
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