比较两个JSON对象,仅返回更改即可返回另一个JSON对象

Gou*_*tam 2 javascript json

我是JavaScript的新手,正在尝试查找两个JSON对象之间的区别。JSON对象及其数据的结构如下所示。我在线获得了一个代码,该代码适用于普通的JSON对象,但是由于它也具有数据数组,因此我认为它不起作用。我尝试了其他事情,但没有结果。如果您对此有指点,将不胜感激。谢谢。

JSON对象1(obj1): {id: 1, details: Array[2], profession: "Business"}

{
  "id": "1",
  "details": [{
      "name": "Peter",
      "address": "Arizona",
      "phone": 9900998899
    },
    {
      "name": "Jam",
      "address": "Kentucky",
      "phone": 56034033343
    }
  ],
  "profession": "Business"
}
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JSON对象2(obj2): {id: 2, details: Array[2], profession: "Business"}

{
  "id": "2",
  "details": [{
      "name": "Peter",
      "address": "Arizona",
      "phone": 9900998899
    },
    {
      "name": "David",
      "address": "Boston",
      "phone": 434323434
    }
  ],
  "profession": "Business"
}
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解:

compare(obj1, obj2) {

  var result = {};

  for (key in obj1) {
    if (obj2[key] != obj1[key]) {
      result[key] = obj2[key];
    }
    if (typeof obj2[key] === '[object Array]' && typeof obj1[key] === '[object Array]') {
      result[key] = compare(obj1[key], obj2[key]);
    }
    if (typeof obj2[key] === 'object' && typeof obj1[key] === 'object') {
      result[key] = compare(obj1[key], obj2[key]);
    }
  }
  console.log(result);
}
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结果:

Object {0: undefined, 1: undefined}
Object {id: "2", pingedAddresses: undefined, type: "Business"}
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预期:

{
  "id": "2",
  "details": [{
    "name": "David",
    "address": "Boston",
    "phone": 434323434
  }]
}
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Raj*_*esh 6

您可以尝试以下简单比较:

注意:此答案假定结构完全相同。您可以以此为参考,并在结构不同的情况下使其更通用。

要考虑的要点:

  • 项目数不同。o1.details有2个条目,o2.details有5个条目。
  • 对象结构不同。两个对象中的属性都不同。

function getDifference(o1, o2) {
  var diff = {};
  var tmp = null;
  if (JSON.stringify(o1) === JSON.stringify(o2)) return;

  for (var k in o1) {
    if (Array.isArray(o1[k]) && Array.isArray(o2[k])) {
      tmp = o1[k].reduce(function(p, c, i) {
        var _t = getDifference(c, o2[k][i]);
        if (_t)
          p.push(_t);
        return p;
      }, []);
      if (Object.keys(tmp).length > 0)
        diff[k] = tmp;
    } else if (typeof(o1[k]) === "object" && typeof(o2[k]) === "object") {
      tmp = getDifference(o1[k], o2[k]);
      if (tmp && Object.keys(tmp) > 0)
        diff[k] = tmp;
    } else if (o1[k] !== o2[k]) {
      diff[k] = o2[k]
    }
  }
  return diff;
}

var o1={id:"1",details:[{name:"Peter",address:"Arizona",phone:9900998899},{name:"Jam",address:"Kentucky",phone:56034033343}],profession:"Business"},
o2={id:"2",details:[{name:"Peter",address:"Arizona",phone:9900998899},{name:"David",address:"Boston",phone:434323434}],profession:"Business"};

var d = getDifference(o1, o2)
console.log(d)
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我写了一个答案来检测物体的变化。您甚至还可以从中获取参考。