如何删除多对括号之间的文本？

Question

我想删除多对括号中的每对之间包含的文本。如果字符串中只有一对括号，则下面的代码可以正常工作：

var text = "This (remove me) works fine!";

// Remove text between brackets.
text = Regex.Replace(text, @"\(.*\)", "");

// Remove extra spaces.
text = Regex.Replace(text, @"\s+", " ");

Console.WriteLine(text);

这工作正常！

但是，如果字符串中包含多组括号，则会删除过多的文本。Regex 表达式删除 FIRST 左括号和 LAST 右括号之间的所有文本。

var text = "This is (remove me) not (remove me) a problem!";

// Remove text between brackets.
text = Regex.Replace(text, @"\(.*\)", "");

// Remove extra spaces.
text = Regex.Replace(text, @"\s+", " ");

Console.WriteLine(text);

这是个问题！

我很难过 - 我确定有一个简单的解决方案，但我没有想法......

帮助最受欢迎！

Answer 1

You have two main possibilities:

• change .* to .*? i.e. match as few as possible and thus match ) as early as possible:

  text = Regex.Replace(text, @"\(.*?\)", "");
  text = Regex.Replace(text, @"\s{2,}", " "); // let's exclude trivial replaces 
  

• change .* to [^)]* i.e. match any symbols except ):

  text = Regex.Replace(text, @"\([^)]*\)", "");
  text = Regex.Replace(text, @"\s{2,}", " ");