我知道SQL中的一些解决方案,但是从SQlite找不到任何解决方案.
我只想执行一个select查询,返回一个从1到100的数字结果集.
Numbers
1
2
3
4
......
5
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更正:我根本没有桌子.(但是像dualMySQL 这样的虚拟表鼓励使用解决方案)
小智 25
谢谢sgmentzer!受到你的回答的启发,我继续发现了这个:
WITH RECURSIVE
cnt(x) AS (
SELECT 1
UNION ALL
SELECT x+1 FROM cnt
LIMIT 100000
)
SELECT x FROM cnt;
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怎么样
SELECT * FROM myTable WHERE myNumber >= 1 AND myNumber <= 100;
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?
小智 6
用于在SQLite中生成系列1 <= n <= 100000的示例子查询.没有创建或使用表.
select 1+e+d*10+c*100+b*1000+a*10000 as n from
(select 0 as a union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9),
(select 0 as b union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9),
(select 0 as c union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9),
(select 0 as d union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9),
(select 0 as e union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9);
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