我希望在屏幕上水平地分隔未知数量的按钮.我想知道我是否可以互相创建他们的间距.例如,下面的代码可以工作吗?
let button1 = UIButton()
let button2 = UIButton()
superview.addSubview(button1)
superview.addSubview(button2)
button1.snp_makeConstraints { (make) -> Void in
make.height.equalTo(100)
make.top.equalTo(50)
make.left.equalTo(superview.snp.left)
make.right.equalTo(button2.snp.right)
make.width.lessThanOrEqualToSuperview()
}
button2.snp_makeConstraints { (make) -> Void in
make.width.lessThanOrEqualToSuperview()
make.height.equalTo(100)
make.top.equalTo(50)
make.left.equalTo(button1.snp.left)
make.right.equalTo(superview.snp.right)
}
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在这种情况下,您应该使用UIStackView带水平轴的a.
也就是说,如果你想使用SnapKit,有很多方法可以做到这一点.我推荐的是这样的:
let count = 3 // or buttons.count if you have an array of buttons
button1.snp.makeConstraints { make in
make.width.equalToSuperview().multipliedBy(1.0 / count)
make.leading.equalToSuperview()
make.top.equalToSuperview().offset(50) // or whatever
make.height.equalTo(100)
}
button2.snp.makeConstraints { make in
make.width.top.height.equalTo(button1)
make.leading.equalTo(button1.snp.trailing)
}
button3.snp.makeConstraints { make in
make.width.top.height.equalTo(button1)
make.leading.equalTo(button2.snp.trailing)
make.trailing.equalToSuperview()
}
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请注意我分别使用leading而trailing不是left和right.这是一个很好的习惯,以便您必须本地化从右到左的语言.然后您的按钮将按照用户设备的自然顺序进行布局.
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