mysql :: insert into table,来自另一个表的数据？

Question

我想知道是否有办法在sql中完全执行此操作:

q1 = SELECT campaign_id, from_number, received_msg, date_received 
     FROM `received_txts` WHERE `campaign_id` = '8';
INSERT INTO action_2_members (campaign_id, mobile, vote, vote_date)    
    VALUES(q1.campaign_id, q1.from_number, q1.received_msg, q1.date_received);

注意: q1将返回大约30k行.

有没有办法在直接sql中做我正在尝试的内容？只是直接从一个表(基本上是原始数据表)中提取数据并插入另一个表(基本上是一个已处理的数据表)？

Answer 1

INSERT INTO action_2_members (campaign_id, mobile, vote, vote_date)  
SELECT campaign_id, from_number, received_msg, date_received
  FROM `received_txts`
 WHERE `campaign_id` = '8'

Answer 2

整排

insert into xyz select * from xyz2 where id="1";

对于选定的列

insert into xyz(t_id,v_id,f_name) select t_id,v_id,f_name from xyz2 where id="1";

Answer 3

由zerkms回答是正确的方法.但是,如果有人想在表中插入更多额外的列,那么您可以从以下内容中获取它:

INSERT INTO action_2_members (`campaign_id`, `mobile`, `email`, `vote`, `vote_date`, `current_time`)
SELECT `campaign_id`, `from_number`, 'example@domain.xyz', `received_msg`, `date_received`, 1502309889 FROM `received_txts` WHERE `campaign_id` = '8'

在上面的查询中,有2个名为email&current_time的额外列.

Answer 4

INSERT INTO Table1 SELECT * FROM Table2