使用jq将JSON转换为CSV

Question

我正在尝试使用sids, ll, state, name, smry我的JSON文件中提取值jq并导出到csv.

JSON文件(out.json):

{
    "data": [
        {
            "meta": {
                "uid": 74529,
                "ll": [
                    -66.9333,
                    47.0667
                ],
                "sids": [
                    "CA008102500 6"
                ],
                "state": "NB",
                "elev": 1250,
                "name": "LONG LAKE"
            },
            "smry": [
                [
                    "42",
                    "1955-02-23"
                ]
            ]
        },
        {
            "meta": {
                "uid": 74534,
                "ll": [
                    -67.2333,
                    45.9667
                ],
                "sids": [
                    "CA008103425 6"
                ],
                "state": "NB",
                "elev": 150.9,
                "name": "NACKAWIC"
            },
            "smry": [
                [
                    "40",
                    "1969-02-23"
                ]
            ]
        },
        {
            "meta": {
                "uid": 74549,
                "ll": [
                    -67.4667,
                    47.4667
                ],
                "sids": [
                    "CA008104933 6"
                ],
                "state": "NB",
                "elev": 794,
                "name": "ST QUENTIN"
            },
            "smry": [
                [
                    "M",
                    "M"
                ]
            ]
        },
        {
            "meta": {
                "uid": 74550,
                "ll": [
                    -67.2667,
                    45.1833
                ],
                "sids": [
                    "CA008104936 6"
                ],
                "state": "NB",
                "elev": 36.1,
                "name": "ST STEPHEN"
            },
            "smry": [
                [
                    "48",
                    "1900-02-23"
                ]
            ]
        },
        {
            "meta": {
                "uid": 74554,
                "ll": [
                    -67.25,
                    47.2667
                ],
                "sids": [
                    "CA008105000 6"
                ],
                "state": "NB",
                "elev": 915.4,
                "name": "SISSON DAM"
            },
            "smry": [
                [
                    "35",
                    "1955-02-23"
                ]
            ]
        }
    ]
}

终端代码:

jq '.data | [ {sids, ll, state, name, smry} ]' out.json

我收到以下错误:

assertion "cb == jq_util_input_next_input_cb" failed: file "/usr/src/ports/jq/jq-1.5-3.x86_64/src/jq-1.5/util.c", line 371, function: jq_util_input_get_position
Aborted (core dumped)

示例预期输出:

sids, ll, state, name, smry
CA008102500, -66.9333, 47.0667, NB, LONG LAKE, 42,1955-02-23
CA008103425, -67.2333, 45.9667, NB, NACKAWIC, 35,1955-02-23

我究竟做错了什么？

Answer 1

这是复杂一点,因为你需要扁平化sids,ll和smry之前您可以拼合全程记录.我建议创建一个jq文件:

foo.jq:

.data[]|{
    "sids":(.meta.sids[0]|split(" ")[0]),
    "ll":(.meta.ll|map(tostring)|join(",")),
    "state":.meta.state,
    "name":.meta.name,
    "smry":(.smry[]|join(","))
}|join(",")
# or, for robust csv output
# } | @csv 

然后打电话:

jq -rf foo.jq file.json

输出:

CA008102500,-66.9333,47.0667,NB,LONG LAKE,42,1955-02-23
CA008103425,-67.2333,45.9667,NB,NACKAWIC,40,1969-02-23
CA008104933,-67.4667,47.4667,NB,ST QUENTIN,M,M
CA008104936,-67.2667,45.1833,NB,ST STEPHEN,48,1900-02-23
CA008105000,-67.25,47.2667,NB,SISSON DAM,35,1955-02-23