从输入字符串中的数组中搜索关键字并打印它们

Question

我几乎在过去的几天里一直这样做,但仍然无法获得所需的输出.好吧,我有一个数组说 wordlist[]={"One","Two","Three","Four","Five"}; ,然后我接受用户的输入.

String input="I have three no, four strings";

现在我想要做的是对字符串执行搜索操作以检查数组wordlist []中可用的单词; 与上面的示例类似,输入字符串包含数组中存在的单词three和four.所以它应该能够从字符串中可用的数组中打印出这些单词,如果没有wordlist []中的单词可用,那么它应该打印"No Match Found".

这是我的代码我很震惊.请

import java.util.regex.*;
import java.io.*;
class StringSearch{
    public static void main(String ...v)throws IOException{
        BufferedReader cin = new BufferedReader(new InputStreamReader(System.in));
        String wordlist[]={"one","two","three","four","five"};
        String input=cin.readLine();
        int i,j;
        boolean found;
        Pattern pat;
        Matcher mat;
        Pattern spliter=Pattern.compile("[ ,.!]");
        String ip[]=spliter.split(input);
        System.out.println(ip[2]);
        for(i=0; i<wordlist.length;i++){
            for(j=0;j<ip.length;j++){
                pat=Pattern.compile("\b"+ip[j]+"\b");
                mat=pat.matcher(wordlist[i]);
                if(){
                        // No Idea What to write here
                }
            }
        }


    }
}

Answer 1

你需要使用matches条件input.matches(".*\\b"+wordlist[i]+"\\b.*")

.* :匹配任何东西

\\b:字边界避免匹配four与fourteen

并且wordlist[i]是你的话

1.)使用循环遍历您的数组

2.)从阵列接字,并使用matches具有给定正则表达式来避免匹配four与fourteen

    String wordlist[]={"one","two","three","four","five"};
    String input="I have three no, fourteen strings";
    int i;
    boolean found=false;
    // Traverse your array
    for(i=0; i<wordlist.length;i++){
           // match your regex containing words from array against input
            if(input.matches(".*\\b"+wordlist[i]+"\\b.*")){
                // set found = true
                found=true;
                // display found matches
                System.out.println(wordlist[i]);
            }
        }
    // if found is false here then mean there was no match
    if (!found) {
        System.out.println("No Match Found");
    }

输出:

three