使用会话进行高级用户验证

san*_*han 5 php session login

我正在建立一个有3种类型用户的网站:

-those who are registered and are subscribed for current month
-those that are registered, but are not subscribed for current month
-users that are not registered (you cant be subscribed if you are not regitered)
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我已经创建了识别这3种用户的代码并且行为恰当.我的问题是,这是要走的路吗?我以前从未做过类似的事情.或者我应该重新编程我的方法?

//login.php

//connect to database and see if a user and password combination exists. Store $exists=0 if not, and $exists=1 if it exists.
session_start();

$conn = new mysqli($hn,$un,$pw,$db);
if ($conn->connect_error){
    die($conn->connect_error);
}
$query = "SELECT COUNT(1) as 'exists',expiration_date FROM table WHERE email = ? AND password = ?;";
$stmt = $conn->prepare($query);
$stmt->bind_param("ss", $email, $password);

$email = $_POST["email"];
$password = hash("hashingalgorithm", "salt".$_POST["password"]."salthere");

$stmt->execute();
   /* Get the result */
$result = $stmt->get_result();
$num_of_rows = $result->num_rows;
$row = $result->fetch_assoc();
$exists = $row["exists"];
$expiration_date = $row["expiration_date"];

/* free results */
$stmt->free_result();

/* close statement */
$stmt->close();
$conn->close();

date_default_timezone_set('Europe/Berlin');


if ($exists==0){
    echo "Wrong email or password";
    $_SESSION['loginerror'] = 2;
    header('Location: https://www.homepage.com/login'); 
}else if ($exists){
    if (strtotime($expiration_date) < (strtotime("now"))){//logged in, but not subscribed
        session_destroy();
        session_start();
        $_SESSION["authenticated"] = true;
        header('Location: https://www.homepage.com');
    }else{//logged in and ready to go
        $_SESSION["authenticated"] = true;
        $_SESSION["email"] = $email;
        header('Location: https://www.homepage.com');
    }
}else{
    echo "An error with has occured.";
} 
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然后在我网站的每一页上我都使用这段代码,看看有哪些用户访问过我

session_start();
if(isset($_SESSION["authenticated"]) && isset($_SESSION["email"])){ 
    $email = $_SESSION["email"];

    //connect to database and fetch expiration_date for a user with $email. Store it in $expiration_date

$conn = new mysqli($hn,$un,$pw,$db);
    if ($conn->connect_error){
        die($conn->connect_error);
    }
    $query = "SELECT expiration_date FROM table WHERE email = ?;";
    $stmt = $conn->prepare($query);
    $stmt->bind_param("s", $email);

    $email = $_SESSION["email"];
    $stmt->execute();
    /* Get the result */
    $result = $stmt->get_result();
    $num_of_rows = $result->num_rows;
    $row = $result->fetch_assoc();
    $expiration_date = $row["expiration_date"];
    /* free results */
    $stmt->free_result();
    /* close statement */
    $stmt->close();
    $conn->close();
    date_default_timezone_set('Europe/Berlin');

    if (strtotime($expiration_date) < (strtotime("now"))){//logged in, but not subscribed
        session_destroy();
        session_start();
        $_SESSION["authenticated"] = true;
        header('Location: https://www.homepage.com');
    }else{  //html for subsribed and registered user
    echo <<<_END
    //html here
    _END;
    }
}else if(isset($_SESSION["authenticated"]) && !isset($_SESSION["email"])){
        // user is logged in, but not subscribed;
        echo <<<_END
        //htmlhere
        _END;
}else{// user is not registered nor is subscribed
        echo <<<_END
        //htmlhere
        _END;
}
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代码有效,但我担心一旦用户注册并订阅,就会在每个页面上访问数据库.我实际上是在惩罚用户注册和订阅.是否有更好的,性能明智的方式来处理这类问题?

Nar*_*ari 1

据我了解,您已经有了一个有效的代码。你问的是意见。您希望删除签入数据库以进行身份​​验证和订阅的每个页面中的重复内容。

在我看来,您需要改变使用会话的方式,

 $_session['email']        // email address of user 
 $_session['auth_type']    // holds authentication type
 $_session['auth_till']    // subscription expire date
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然后让我们创建函数来检查订阅。该函数可以放入单独的文件中,例如:init.php。在这里我们可以放置会话启动机制,以便在任何情况下会话都可用。

if(!isset($_SESSION)) 
    session_start();       // start session if not already started

// lets define global vars to hold authentication type of visitor
define("SUBSCRIBED",1); 
define("UN_SUBSCRIBED",2);
define("REGISTERED",3);
function checkSubscription():bool{
    $return = false;
    if(($_session['auth_type']==SUBSCRIBED)&&(strtotime($_session['auth_till']) < strtotime("now")))
        $return= true;
    return $return
}
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在 login.php 上使用相同的技术,同时设置会话身份验证类型。

现在任何其他页面都可以简单地使用函数来检查订阅

例如:

<?php
// file: product.php
include_once("init.php");
if(!checkSubscription()){
    // subscription finished. do what you need to do. otherwise continue.
}
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您的代码可以进行许多改进。但我认为这可以满足您的需求。如果您需要任何进一步的帮助,请告诉我。请访问Scape并告诉我那里是否有任何有用的编码。