如何根据标签获取类似的对象

Question

我有三个这样的表:

• 电影:身份证,姓名

• tag:id,name,value

• 已标记:id,movie(FK),tag(FK)

因此,每部电影都有自己的一组标签.我需要的是根据标签集检索类似的电影.我想说出按照匹配标签的数量排序的10部电影.

如果我创建如下的视图,它会让MySQL消失."tag"和"tagged"表中都有30k +条记录.

create view relatedtags as 

select
    entityLeft.id as id,
    entityRight.id as rightId,
    count(rightTagged.id) as matches

from
    entity as entityLeft join tagged as leftTagged on leftTagged.entity = entityLeft.id, 
    entity as entityRight join tagged as rightTagged on rightTagged.entity = entityRight.id

where leftTagged.tag = rightTagged.tag
and entityLeft.id != entityRight.id
group by entityLeft.id, entityRight.id

Answer 1

这将返回所有电影的列表,这些电影共享至少1个标签,并且<current_movie_id>通过减少共同的标签数量来排序

SELECT movie.*, count(DISTINCT similar.tag) as shared_tags FROM movie INNER JOIN 
    ( tagged AS this_movie INNER JOIN tagged AS similar USING (tag) )
    ON similar.movie = movie.id
WHERE this_movie.movie=<current_movie_id>
AND   movie.id != this_movie.movie
GROUP BY movie.id
ORDER BY shared_tags DESC

希望能给你一些合作的东西