我如何总结 django 模型的内容

sim*_*vic 2 python django sum calculation

我有这个模型:

class Transfer(models.Model):
        transfer_code = models.CharField(max_length=30, blank=True, null=True)
        sender_name = models.CharField(max_length=30, blank=True, null=True)
        amount = models.IntegerField(blank=True, null=True)
        recipient_name = models.CharField(max_length=30, blank=True, null=True)
        time_sent = models.DateTimeField(auto_now_add=True, auto_now=False)
        received = models.BooleanField(default=False)
        time_received = models.DateTimeField(auto_now_add=False, auto_now=False, null=True)

        def __unicode__(self):
            return self.transfer_code
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这是我想计算表中总金额的视图:

def listtransfersall(request):
    title = 'ALL TRANSFERS'
    queryset = Transfer.objects.all()
    for instance in queryset:
        total = 0
        total += instance.amount
        print total

    context = {
    "title": title,
    "queryset": queryset,
    "total": total,
    }
    return render(request, "listtransfersall.html",context)
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这将单独打印表中的金额。如何获得总数并将其分配给 total 变量?

Jon*_*sky 6

在您发布的代码中,您total = 0每次都通过循环进行设置

for instance in queryset:
    total = 0
    total += instance.amount
    print total
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将该行移到循环之外,这将按照您的预期工作。

稍微好一点的是得到一个values_list和总和:

amounts = Transfer.objects.values_list('amount', flat=True)
total = sum(amounts)
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更好的是让数据库完成工作并使用 Sum 聚合:

from django.db.models import Sum
total = Transfer.objects.aggregate(Sum("amount"))
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有关聚合的更多信息,请参阅文档