chk*_*ddi 1 java collections deque
我创建了一个DeQueue作为follws
Deque<Integer> deque = new ArrayDeque<Integer>(8);
// use add() method to add elements in the deque
deque.add(20);
deque.add(30);
deque.addLast(12);
deque.add(18);
deque.addFirst(22);
deque.add(24);
// let us print all the elements available in deque
for (Integer number : deque) {
System.out.println("Number = " + number);
}
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预期的产出是:
Number = 22
Number = 20
Number = 30
Number = 18
Number = 24
Number = 12
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但实际输出是:
Number = 22
Number = 20
Number = 30
Number = 12
Number = 18
Number = 24
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有人请解释一下吗?
addLast
不会以某种方式永远保持"这应该是最后的"的概念 - 它只会增加当前出列的结尾.据记载add
,这相当于.
因此,如果我们查看每个步骤的值,我们有:
deque.add(20); // Contents: 20
deque.add(30); // Contents: 20, 30
deque.addLast(12); // Contents: 20, 30, 12
deque.add(18); // Contents: 20, 30, 12, 18
deque.addFirst(22); // Contents: 22, 20, 30, 12, 18
deque.add(24); // Contents: 22, 20, 30, 12, 18, 24
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......这与你得到的输出完全一致.
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