Kou*_*sha 26 javascript reactjs
我需要至少制作一个所需的道具:
MyComponent.propTypes = {
data: PropTypes.object,
url: PropTypes.string
};
Run Code Online (Sandbox Code Playgroud)
因此,在上面的例子中,必须提供data
或者url
必须提供.这里的用例是用户可以提供data
或者url
.如果url
提供了,那么组件将获取data
.
奖金问题:我如何做至少一个道具vs只有一个道具?
fin*_*req 33
PropTypes实际上可以将自定义函数作为参数,因此您可以执行以下操作:
MyComponent.propTypes = {
data: (props, propName, componentName) => {
if (!props.data && !props.url) {
return new Error(`One of props 'data' or 'url' was not specified in '${componentName}'.`);
}
},
url: (props, propName, componentName) => {
if (!props.data && !props.url) {
return new Error(`One of props 'url' or 'data' was not specified in '${componentName}'.`);
}
}
}
Run Code Online (Sandbox Code Playgroud)
这允许客户错误消息.使用此方法时,只能返回null或Error
你可以在这里找到更多信息
https://facebook.github.io/react/docs/typechecking-with-proptypes.html#react.proptypes
来自反应文档:
// You can also specify a custom validator. It should return an Error
// object if the validation fails. Don't `console.warn` or throw, as this
// won't work inside `oneOfType`.
customProp: function(props, propName, componentName) {
if (!/matchme/.test(props[propName])) {
return new Error(
'Invalid prop `' + propName + '` supplied to' +
' `' + componentName + '`. Validation failed.'
);
}
},
Run Code Online (Sandbox Code Playgroud)
Bea*_*ith 15
@ finalfreq解决方案的更简洁版本:
const requiredPropsCheck = (props, propName, componentName) => {
if (!props.data && !props.url) {
return new Error(`One of 'data' or 'url' is required by '${componentName}' component.`)
}
}
Markdown.propTypes = {
data: requiredPropsCheck,
url: requiredPropsCheck,
}
Run Code Online (Sandbox Code Playgroud)