使用谷歌测试来检查回调

Kon*_*tin 5 c++ googletest googlemock

我有一个类Foo存储指向回调的指针.可以使用方法调用回调InvokeCallback().

void* SomeCallback(void* a) {

  return (void*)(*(int*)a + 10);

}


class Foo {

public: 

    typedef void* (*CallbackFunction)(void*);

    SetCallback(CallbackFunction callback) {
        this->callback = callback;
    }

    InvokeCallback() {
        callback(20);
    }

private:

    CallbackFunction callback;

}
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如何测试(使用谷歌测试)SomeCallback()使用特定参数调用(在上述情况下为20)?

编辑:

我提出了一个非常难看的解决方案.测试通过,但最后出现了新的错误ERROR: 1 leaked mock object found at program exit.

class MockCallbackClass {
public:
    MOCK_METHOD1(SomeCallback, void*(void*));
};

MockCallbackClass mock; // Nasty global variable

void* __SomeOtherCallback(void* a) {

    return mock.SomeCallback(a);

}

TEST(Callback, MockCallback) {

    Foo foo;
    foo.SetCallback(__SomeOtherCallback);
    EXPECT_CALL(mock, SomeCallback((void*)10)).WillOnce(testing::Return((void*)20));

}
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Pio*_*ycz 9

使用std::function<void*(void*)>testing::MockFunction<void*(void*)>嘲笑这个std::function.当然,这需要对您的实现稍作修改 - 但您的设计功能不会改变,因为原始函数指针可以std::function毫无问题地存储:

class Foo {
public: 

    using CallbackFunction = std::function<void*(void*)>;
    // rest of this class is as it was
};
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并测试如下:

class FooTest : public testing::Test {
public: 

    using CallbackFunctionMock = testing::MockFunction<void*(void*)>;
    CallbackFunctionMock  callbackFunctionMock;

    Foo  objectUnderTest{[this](void* v) { return callbackFunctionMock.Call(v); }};
};
TEST_F(FooTest, shallCallbackBeCalledByInvoke)
{
    int a = 40;
    EXPECT_CALL(callbackFunctionMock, Call(reinterpret_cast<void*>(20)).WillOnce(Return((void*)(&a));
    objectUnderTest.InvokeCallback();
}
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